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Rina8888 [55]
2 years ago
13

Describe the solubility of al(oh3 with respect to ph.

Chemistry
1 answer:
BartSMP [9]2 years ago
6 0
The solubility of Al(OH)3 with respect to pH is <span>soluble at low pH, insoluble in pH-neutral solution, and soluble at high pH. We can express it as this:
</span>Solubility equilibrium expression for Al(OH)3 is 
<span>Al(OH)3 <==> Al3+(aq) + 3OH-(aq) </span>
<span>Initial 0 1.0x10^-3 M </span>
<span>change +s +3s 
</span>Remember that s<span>olubility is used in chemistry to describe the properties of a solid compound that is mixed with and fully dissolves in a fluid without leaving any undissolved particles.</span>
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3 years ago
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Basile [38]

Answer:

The answer of this question is molecule

4 0
3 years ago
3.65 gram of hcl is dissolved in 180 gram of water. Find the total number of molecules of hydrogen​
Morgarella [4.7K]

Answer:

Molec_{\ H_{tot}}=1.206x10^{25}molec

Explanation:

Hello.

In this case, taking into account that HCl has one molecule of hydrogen per mole of compound which weights 36.45 g/mol, we compute the number of molecules of hydrogen in hydrochloric acid by considering the given mass and the Avogadro's number:

molec_{\ H}=3.65gHCl*\frac{1molHCl}{36.45gHCl} *\frac{1molH}{1molHCl}*\frac{6.022x10^{23}molec_\ H}{1molH}  =6.03x10^{22}molec

Now, from the 180 g of water, we see two hydrogen molecules per molecule of water, thus, by also using the Avogadro's number we compute the molecules of hydrogen in water:

molec_{\ H}=180gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O}*\frac{6.022x10^{23}molec_\ H}{1molH}  =1.20x10^{25}molec

Thus, the total number of molecules turns out:

Molec_{\ H_{tot}}=6.03x10^{22}+1.20x10^{25}\\\\Molec_{\ H_{tot}}=1.206x10^{25}molec

Regards.

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3 years ago
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2 years ago
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