Answer:
32.6 %
Explanation:
Given data
- Mass of sucrose (solute): 22.8 grams
- Mass of water (solvent): 47.1 grams
Step 1: Calculate the mass of the solution
The mass of the solution is equal to the sum of the mass of the solute and the mass of the solvent.
m(solution) = m(solute) + m(solvent)
m(solution) = 22.8 g + 47.1 g
m(solution) = 69.9 g
Step 2: Calculate the percent-by-mass of sucrose in the solution
We will use the following expression.

I thinks it's C although I'm not 100% positive.
This means that the air in that city has less than a third of water vapor it could contain under the same circumstances. Relative humidity is the ratio of water vapor that the air contains to the maximum amount it could carry at the same temperature. When the humidity is high the water vapor in the air is a lot and vice versa.
Answer:
8.25 g HNO3 (please correct me if I'm wrong!)
FeCl₂ + 2NH₄OH → Fe(OH)₂ + 2NH₄Cl