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VMariaS [17]
2 years ago
5

How many solutions does the system have? zero one two three four infinitely many.

Chemistry
1 answer:
Ber [7]2 years ago
4 0

Answer:

the system has infinitely many solutions.

Explanation:

The system is 2x + y = 1 and 4x + 2y = 2. Solutions to a system are the intersection points. Since these two lines are the same line they intersect everywhere. There are infinitely many solutions.

hope this helps

plz mark brainliest

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can someone help me more clearly understand the difference between heterogeneous and homogeneous? Give an example of each plz.
const2013 [10]
Heterogenous mixtures are unevenly mixed. Like oil and vinegar in vinaigrette if it is not emulsified well enough and they separate. Any case where two things are not evenly distributed within each other.

Homogenous mixtures are evenly mixed throughout. Like salt water or kool-aid (when it's mixed).

Hope this helps!
3 0
3 years ago
How did your estimated poputation size<br> compare with the actual population size
musickatia [10]

Answer:

Hope this helps

Explanation:

https://seagrant.whoi.edu/wp-content/uploads/2018/05/ESTIMATING-POPULATION-SIZE-1.pdf

8 0
3 years ago
Read 2 more answers
This feature of a volcano is called an____________________which releases heated ash and Tephra through its column generating its
trapecia [35]

Answer:

Volcanic Eruption releases heated ash and Tephra through its column generating its own lightning.

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7 0
3 years ago
A military jet cruising at an altitude of 12.0km and speed of 1300./kmh burns fuel at the rate of 46.2/Lmin. How would you calcu
ira [324]

Answer:

2,452.12 L of fuel the jet consumes on a 1150 km mission.

Explanation:

Speed of the jet = 1300 km/h

1 hour = 60 minutes

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Rate at which jet consumes fuel = 46.2 L/min

Distance covered by jet by consuming 1 liter fuel or mileage = R

R = \frac{21.667 km/min}{46.2 L/min}=0.4690 km/L

The amount of fuel the jet consumes on a 1150 km mission will = V

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2,452.12 L of fuel the jet consumes on a 1150 km mission.

3 0
3 years ago
Calculate the mass of water produced when 6.97 g of butane reacts with excess oxygen
andrew-mc [135]
The balanced reaction equation for the combustion of butane is as follows;
C₄H₁₀ + 13/2O₂ ---> 4CO₂ + 5H₂O 
the limiting reactant in this reaction is C₄H₁₀  This means that all the butane moles are consumed and amount of product formed depends on the amount of C₄H₁₀ used up.
stoichiometry of C₄H₁₀ to H₂O is 1:5
mass of butane used - 6.97 g
number of moles - 6.97 g / 58 g/mol = 0.12 mol
then the number of water moles produced - 0.12 mol x 5 = 0.6 mol
Therefore mass of water produced - 0.6 mol x 18 g/mol = 10.8 g
7 0
3 years ago
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