Answer:
see explanation below
Explanation:
You miss the part of the temperature and pressure. According to what I found this is held under 30 °C (or 303 K) and 1 atm.
The problem states that we can treat this gas as an ideal gas, therefore, we can use the equation of an ideal gas which is:
PV = nRT (1)
Now, the density (d) is calculated as:
d = m/V (2)
We can rewrite (2) in function of mass of volume so:
m = d*V (3)
Now, the moles (n) of (1) can be calculated like this:
n = m /MM (4)
If we replace it in (1) and then, (3) into this we have the following:
PV = mRT/MM ----> replacing (3):
PV = dVRT/MM ----> V cancels out so finallly:
P = dRT/MM
d = P * MM / RT (5)
The molar mass of N2O is 44 g/mol So, replacing all the data we have:
d = 1 * 44 / 0.082 * 303
d = 1.77 g/L
Answer:
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Explanation:
Copper ions, nitrate ions, and water is in the beaker
2 ways to do this
a. find %Cl in CaCl2
2 x 35.45g/mole = 70.9g Cl
70.9g Cl / 110.9g/mole CaCl2 = 63.93% Cl in CaCl2
0.6963 x 145g = 92.7g = mass Cl
b. determine moles CaCl2 present then mass Cl
145g / 110.9g/mole = 1.31moles CaCl2 present
2moles Cl / 1mole CaCl2 x 1.31moles = 2.62moles Cl
2.62moles Cl x 35.45g/mole = 92.7g Cl
