A chemist adds 0.85 L of a 0.0050M calcium sulfate to a reaction flask. Calculate the mass in grams of calcium sulfate the chemist has added to the flask. Round your answer to significant digits.

Answer: The mass in grams of calcium sulfate the chemist has added to the flask is 0.58 g

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L

moles of $CaSO_4$ = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{136g/mol}$

Now put all the given values in the formula of molarity, we get

$0.0050=\frac{x}{136\times 0.85}$

$x=0.58 g$

Therefore, the mass in grams of calcium sulfate the chemist has added to the flask is 0.58 g

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