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3 years ago

The quantity represented by vi is a function of time (i.e., is not constant).A. TrueB. False

Physics

1 answer:

iris [78.8K]3 years ago

7 0

Answer:

The answer is false

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Density is calculated by:

taurus [48]

Answer:

divide by mass and volume

Explanation:

density=mass/volume

or in symbols:p=m/v

6 0

3 years ago

Read 2 more answers

Two point charges are placed on the x axis.The firstcharge, q1= 8.00 nC, is placed a distance 16.0 mfromthe origin along the pos

deff fn [24]

Answer:

E = (0, 0.299) N

Explanation:

Given,

Charge $q_1\ =\ 8.0\ nC$
Charge $q_2\ =\ 6.0\ nC$
Distance of the first charge from the origin = (16m, 0)
Distance of the second charge from the origin = (-9, 0)
Point where the electric field required = (0, 12m)

Let $\theta_1\ and\ theta_2$ be the angle of the electric fields by first and second charge at the point A.

$\therefore sin\theta_1\ =\ \dfrac{12}{20}\\\Rightarrow \theta_1\ =\ sin^{-1}\left (\dfrac{12}{20}\ \right )\\\Rightarrow \theta_1\ =\ 36.87^o\\\\\therefore sin\theta_1\ =\ \dfrac{12}{9}\\\Rightarrow \theta_1\ =\ sin^{-1}\left (\dfrac{12}{9}\ \right )\\\Rightarrow \theta_1\ =\ 53.13^o\\$

Electric field by charge $q_1$ at point A,

$F_1\ =\ \dfrac{kq_1}{r_1^2}\\\Rightarrow F_1\ =\ \dfrac{9\times 10^9\times 8\times 10^{-9}}{20^2}\\\Rightarrow F_1\ =\ 0.18\ N/C$

Electric field by the charge $q_2$ at point A,

$F_1\ =\ \dfrac{kq_1}{r_1^2}\\\Rightarrow F_1\ =\ \dfrac{9\times 10^9\times 6.0\times 10^{-9}}{16^2}\\\Rightarrow F_1\ =\ 0.24\ N/C$

Now,

Net electric field in horizontal direction at point A $F_x\ =\ F_{1x}\ +\ F_{2x}\\\Rightarrow F_x\ =\ F_1cos\theta_1\ +\ F_2cos\theta_2\\\Rightarrow F_x\ =\ 0.18\times( -cos36.87^o)\ +\ 0.24\times cos53.13^o\\\Rightarrow F_x\ =\ -0.144\ +\ 0.144\ N/C\\\Rightarrow F_x\ =\ 0\ N/C$

Net electric field in vertical direction at point A.

$F_y\ =\ F_{1y}\ +\ F_{2y}\\\Rightarrow F_y\ =\ F_1sin\theta_1\ +\ F_2sin\theta_2\\\Rightarrow F_y\ =\ 0.18\times sin36.87^o\ +\ 0.24\times sin53.13^o\\\Rightarrow F_y\ =\ 0.180\ +\ 0.192\\\Rightarrow F_y\ =\ 0.299\ N/C$

Hence, the net electric field at point A,

$F\ =\ ( 0, 0.299 )\ N/C.$

5 0

3 years ago

You are designing a manned submersible to withstand the pressure of seawater at the bottom of the Mariana Trench, which is one o

elena55 [62]

Answer:

110029941 Pa

311388.81857 N

286.48968 N

Explanation:

$P_0$ = Atmospheric pressure = 101325 Pa

$\rho$ = Density of seawater = 1029 kg/m³

h = Depth = 10900 m

g = Acceleration due to gravity = 9.81 m/s²

r = Radius = 3 cm

A = Area = $\pi r^2$

Gauge pressure

$P_g=\rho gh\\\Rightarrow P_g=1029\times 9.81\times 10900\\\Rightarrow P_g=110029941\ Pa$

The gauge pressure is 110029941 Pa

Net pressure at the given depth

$P=P_0+\rho gh\\\Rightarrow P=101325+1029\times 9.81\times 10900\\\Rightarrow P=110131266\ Pa$

Force is given by

$F=PA\\\Rightarrow F=110131266\times \pi 0.03^2\\\Rightarrow F=311388.81857\ N$

The force is 311388.81857 N

Now if P = 1 atm

$F=101325\times \pi 0.03^2\\\Rightarrow F=286.48968\ N$

The force is 286.48968 N

7 0

3 years ago

Draw the force vector starting at the black dot. The location, orientation, and length of the vector will be graded. You can mov

alisha [4.7K]

Answer:

F3 is the equilibrant force equal in magnitude to the resultant between F1 and F2 but opposite in direction to it.

Explanation:

Given the diagram, the force F3 to make the body remain at rest or in equilibrium is the equilibrant force, this force is equal in magnitude to the resultant Fr between F1 and F2 but opposite in direction to it.

See attachment for diagram of forces.

The resultant force;

Fr =√ (F1)² + (F2)²...(1) [diagram a]

Therefore the length of F3 is Fr

F3 = -Fr

The direction (diagram b) of the resultant force Fr is given by

∆ = acrtan[(F1/F2)]

The direction of F3 is [90 + arctan(F1/F2)]

As seen in the diagram (d), the location of the force is in the fourth quadrant.

3 0

3 years ago

Henri draws a wave that has a 4 cm distance between the midpoint and the trough. Geri draws a wave that has an 8 cm vertical dis

andre [41]

Answer:

Henri’s wave and Geri’s wave have the same amplitude and the same energy

Explanation:

The amplitude of a wave is the distance between the midpoint and the trough (or the crest). This is equivalent to half the distance between the trough and the crest. Therefore:

amplitude of Henri's wave: 4 cm

amplitude of Geri's wave: 8/2 = 4 cm

The energy of a wave is directly proportional to its amplitude.

6 0

3 years ago

Read 2 more answers