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Ira Lisetskai [31]
3 years ago
9

Jared would describe a square as having four equal sides and four right angles. This is Jared’s __________ of a square. A. model

B. hierarchy C. feature D. concept Please select the best answer from the choices provided A B C D
Physics
1 answer:
zheka24 [161]3 years ago
4 0

Answer:

D

Explanation:

jhusskgtyddutsuudtiff

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kirill115 [55]
Tornado- Trees knocked down, debris everywhere, ground and dirt scattered.
7 0
3 years ago
An airplane is heading due south at a speed of 430 km/h . A wind begins blowing from the northwest at a speed of 85.0 km/h (aver
Igoryamba

Answer:

It should fly 8° to west of south at 430km/h

Explanation:

According to the diagram. X components for both velocities must have the same magnitude in order to get the resultant velocity due south.

V_{w}*cos(45) = V_{A}*sin(\alpha )   Solving for α:

α = 8.03°

5 0
3 years ago
If you were to apply a force of 15N to a medicine ball with a mass of 10kg, what would its acceleration be
tresset_1 [31]

One of the equations for force is:  Force = mass × acceleration.

The force and mass are given and so:

F=15N

m=10kg

By plugging in these values we obtain:

F=ma\\\\15=10(a)\\

\frac{15}{10}=\frac{10(a)}{10}\\\\a=\frac{15}{10}=1.5m/s^2

So the acceleration is a=1.5m/s^2

6 0
3 years ago
hat are the wavelengths of peak intensity and the corresponding spectral regions for radiating objects at (a) normal human body
bagirrra123 [75]

Answer:

(a)

\lambda _{m}=9.332 \times 10^{-6}m

(b)

\lambda _{m}=1.632 \times 10^{-6}m

(c) \lambda _{m}=4.988 \times 10^{-7}m

 

Explanation:

According to the Wein's displacement law

\lambda _{m}\times T = b

Where, T be the absolute temperature and b is the Wein's displacement constant.

b = 2.898 x 10^-3 m-K

(a) T = 37°C = 37 + 273 = 310 K

\lambda _{m}=\frac{b}{T}

\lambda _{m}=\frac{2.893\times 10^{-3}}{310}

\lambda _{m}=9.332 \times 10^{-6}m

(b) T = 1500°C = 1500 + 273 = 1773 K

\lambda _{m}=\frac{b}{T}

\lambda _{m}=\frac{2.893\times 10^{-3}}{1773}

\lambda _{m}=1.632 \times 10^{-6}m

(c) T = 5800 K

\lambda _{m}=\frac{b}{T}

\lambda _{m}=\frac{2.893\times 10^{-3}}{5800}

\lambda _{m}=4.988 \times 10^{-7}m

5 0
3 years ago
A Chevrolet Corvette convertible can brake to a stop from a speed of 60.0 mi/h in a distance of 123 ft on a level roadway. What
Digiron [165]

Answer:

83.1946504051 m

Explanation:

u = Initial velocity = 60\ mph=\dfrac{60\times 1609.34}{3600}=26.82233\ m/s

s = Displacement = 123\ ft=\dfrac{123}{3.281}=37.4885705578\ m

\theta = Angle = 26^{\circ}

v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{0^2-26.82233^2}{2\times 37.4885705578}\\\Rightarrow a=-9.5954230306\ m/s^2

Coefficient of friction

\mu=-\dfrac{a}{g}\\\Rightarrow \mu=\dfrac{9.5954230306}{9.81}\\\Rightarrow \mu=0.978126710561

mg sin\theta - u mg cos\theta = ma\\\Rightarrow a=9.81(sin26-0.978126710561cos26)\\\Rightarrow a=-4.32382\ m/s^2

v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-26.82233^2}{2\times -4.32382}\\\Rightarrow s=83.1946504051\ m

The stopping distance is 83.1946504051 m

6 0
4 years ago
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