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3 years ago

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A given solution has 42.5 g NaNO3 in 1500 mL of water. What is the molarity of this solution? Show your work, rounding the atomi

c mass of each element to the nearest tenth and your final answer to the nearest hundredth

2 answers:

lutik1710 [3]3 years ago

5 0

Explanation:

here's the answer to your question

Marrrta [24]3 years ago

3 0

Ur mom? lol jk i don't know this one

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3 years ago

the student determines the molar mass of the gas to be 64 g mol-1. write the expression (set-up) for calculating the percent err

sleet_krkn [62]

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Percentage error = $\frac{(64 - 58)}{58}$ x 100%

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In order to calculate the percentage error in the student's calculation, the following formula will be used:

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experimental molar mass = 64 g/mol

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Percentage error = $\frac{(64 - 58)}{58}$ x 100%

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