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3 years ago

Find the area of the rectangle with the given base and height.

Mathematics

1 answer:

Temka [501]3 years ago

5 0

Answer: 3 1/3 ft^2

Step-by-step explanation:

Start by converting the inches into feet

1 ft = 12 in

4 in/1 x 1 ft/ 12 in = 4/12 ft = 1/3 ft

Now, imagine just multiply like normal for a rectangle:

Area of a rectangle = base x height

Area of rectangle = (10 ft) (1/3 ft)

Area of rectangle = 3 1/3 ft^2

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Alex_Xolod [135]

i think 2,1,3 but that is just my opinion

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2 years ago

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Help? I forgot how to do this lol I have really bad memory

pashok25 [27]

$\dfrac{2}{3} \times \dfrac{3}{4} \times \dfrac{1}{2}$

Cancel out 2, the common factor for the numerator and denominator:

$= \dfrac{1}{3} \times \dfrac{3}{4} \times \dfrac{1}{1}$

Cancel out 3, the common factor for the numerator and denominator:

$= \dfrac{1}{1} \times \dfrac{1}{4} \times \dfrac{1}{1}$

Combine into single fraction:

$= \dfrac{1 \times 1 \times 1}{1 \times 4 \times 1 } = \dfrac{1}{4}$

$\bf \text {Answer = } \dfrac{1}{4}$

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3 years ago

Remy, from the blog "Rapping with Remy," asked his readers, "If you had the chance, would you want to be famous?" Of the 2,200 r

astraxan [27]

Answer:

This was a legitimate sample, drawn randomly from his readers, and is of adequate size to allow the conclusion that most of Remy's readers want to be famous.

Step-by-step explanation:

Assuming that only YES and NO option were available to Remy's reader.

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which shows that more of readers readers would want to be famous.

which agrees with the option E

This was a legitimate sample, drawn randomly from his readers, and is of adequate size to allow the conclusion that most of Remy's readers want to be famous.

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3 years ago

kipiarov [429]

Hope it a right answer for you

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3 years ago

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Simora [160]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\$

$\bf \textit{\underline{m} varies directly with the amount of gallons}\implies \stackrel{months}{m}=k\stackrel{gallons}{g}
\\\\\\
\textit{we also know that }
\begin{cases}
m=1\frac{1}{3}\\
\qquad \frac{4}{3}\\
g=1
\end{cases}\implies \cfrac{4}{3}=k1\implies \cfrac{4}{3}=k
\\\\\\
\boxed{m=\cfrac{4}{3}g}\\\\
-------------------------------\\\\
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3 years ago