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rewona [7]
3 years ago
13

Define weak force and strong force pls need it thanks so much :) :)

Chemistry
1 answer:
Semmy [17]3 years ago
6 0
In particles physics, the weak interaction (the weak force or weak nuclear force) is one of the four known fundamentals interactions of nature, alongside the strong interaction, electromagnetism, and gravitation.
 
 This is based on my research, hope it helped :) <span />
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H202-h20-o2<br> In this process oxygen gas is a
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Oxgeyn gas liquid.

Explanation:

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3 years ago
a mixture containing 21.4 g of ice. (0.00 c) and 75.3 g of water (55.3 c) is placed in an insulatated container
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What is the crystalline arrangement of atoms shown here?
mixer [17]

Answer: Answer:

"The arrangement of atoms or ions in a crystal " is described by the terms body-centered cubic and face-centered cubic.

Explanation:

Face centred cubic system explains the crystal structure where an atom is present at each cubic corner of the crystal  and the centre of each cube face. Meaningfully, a closed packed plane where at each "face of the cube" atoms touch the alongside face diagonals.

Whereas in body centric cube system has the lattice point present at the 8 corners of  cell and an additional one at the center of the cell. Thus, both explains how the atom or ions are  placed or arranged in a crystal.

Explanation: Hope this helps :)

4 0
3 years ago
If a piece of cadmium with a mass of 37.60 g and a temperature of 100.0 oC is dropped into 25.00 cc of water at 23.0 oC, what wi
zlopas [31]

Answer:

T_{eq}=28.9\°C

Explanation:

Hello!

In this case, since it is observed that hot cadmium is placed in cold water, we can infer that the heat released due to the cooling of cadmium is gained by the water and therefore we can write:

Q_{Cd}+Q_{W}=0

Thus, we insert mass, specific heat and temperatures to obtain:

m_{Cd}C_{Cd}(T_{eq}-T_{Cd})+m_{W}C_{W}(T_{eq}-T_{W})=0

In such a way, since the specific heat of cadmium and water are respectively 0.232 and 4.184 J/(g °C), we can solve for the equilibrium temperature (the final one) as shown below:

T_{eq}=\frac{m_{Cd}C_{Cd}T_{Cd}+m_{W}C_{W}T_{W}}{m_{Cd}C_{Cd}+m_{W}C_{W}}

Now, we plug in to obtain:

T_{eq}=\frac{37.60g*0.232\frac{J}{g\°C}*100.00\°C+25.00g*4.184\frac{J}{g\°C}*23.0\°C}{37.60g*0.232\frac{J}{g\°C}+25.00g*4.184\frac{J}{g\°C}}\\\\T_{eq}=28.9\°C

NOTE: since the density of water is 1g/cc, we infer that 25.00 cc equals 25.00 g.

Best regards!

6 0
2 years ago
Which is best represented by the equation?
sergeinik [125]
A- law of conservation of energy
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3 years ago
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