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Bess [88]
4 years ago
3

Make the conversion indicated ineach of the following:

Chemistry
2 answers:
mars1129 [50]4 years ago
6 0

Answer:

a. 8.94715 meters

b. 10.460736 km

c. 251180.79 km²

d. 118.294118 milliliters

e. 1375440000 km³

f.  1598.9131043 kg

g.  65.203903130 grams

Explanation:

(a) The men's world record long jump 29 ft 4 1/4 in to meters

29 ft 17/4 inches

1 ft = 0.3048 meters

29 ft = ?

cross multiply

29 × 0.3048

8.8392 meters

1 inch = 0.0254 meters

4.25 inch = ?

0.10795 meters

8.8392 meters + 0.10795 meters = 8.94715 meters

(b) the greatest depth of the ocean, about 6.5 mi, to kilometers

1 mile = 1.609344 km

6.5 miles = ?

6.5 × 1.609344

= 10.460736 km

(c) the area of the state of Oregon, 96,981 mi2, to square kilometers  h

1 mile² = 2.59 km²

96,981 = ?

96,981 × 2.59

251180.79 km²

(d) the volume of 1 gill (exactly 4 oz) to milliliters

1 gill = 118.294118 milliliters

118.294118 milliliters

(e) the esimated volume of the oceans, 330,000,000 mi3, to cubic kilometers.

1 mile³ = 4.168 km³.

330,000,000 mile³ = ?

330,000,000 × 4.168 =  1375440000 km³

(f) the mass of a 3525-Ib car to kilograms

1 Ib = 0.45359237  kg

3525 Ib  = ?

3525 × 0.45359237 = 1598.9131043 kg

(g) the mass of a 2.3-oz egg to grams

1 oz = 28.3495231 grams

2.3 oz = ?

2.3 × 28.3495231  = 65.203903130 grams

Aneli [31]4 years ago
5 0

Answer:

a) 8.947 m

b) 10.46 Km

c) 251.178 Km²

d) 118.294 mL

e) 1375489746 Km³

f) 1598.912 Kg

g) 65.204 g

Explanation:

a) 4 1/4 in (4.25 in) = 0.3542 ft ⇒ 29 ft 4 1/4 in = 29.3542 ft * ( m / 3.28084 ft ) = 8.947 m

b) 6.5 mi * ( 1.60934 Km / mi ) = 10.46 Km

c)  96.981 mi² * ( 1.60934 Km / mi )² = 251.178 Km²

d) 4 Oz * ( 29.5735 mL / Oz ) = 118.294 mL

e) 330000000 mi³ * ( 1609.34 m /  mi )³ * ( Km / 1000 m )³  = 1375489746 Km³

f) 3525 Lb * ( 0.453592 Kg / Lb ) = 1598.912 Kg

g) 2.3 Oz * ( 28.3495 g / Oz ) = 65.204 g

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Explanation: Mass is the amount of matter contained in a body.

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Addition of an excess of lead (II) nitrate to a 50.0mL solution of magnesium chloride caused a formation of 7.35g of lead (II) c
KiRa [710]

Answer:

[Cl⁻] = 0.016M

Explanation:

First of all, we determine the reaction:

Pb(NO₃)₂ (aq) + MgCl₂ (aq) → PbCl₂ (s) ↓  +  Mg(NO₃)₂(aq)

This is a solubility equilibrium, where you have a precipitate formed, lead(II) chloride. This salt can be dissociated as:

           PbCl₂(s)  ⇄  Pb²⁺ (aq)  +  2Cl⁻ (aq)     Kps

Initial        x

React       s

Eq          x - s              s                  2s

As this is an equilibrium, the Kps works as the constant (Solubility product):

Kps = s . (2s)²

Kps = 4s³ = 1.7ₓ10⁻⁵

4s³ = 1.7ₓ10⁻⁵

s =  ∛(1.7ₓ10⁻⁵ . 1/4)

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3 0
3 years ago
In one of the routine analyses, Dr Entropy found that the concentration of phosphate had increased from 0.0090 mg/L to 0.220 mg/
wariber [46]

Answer:

The final volume should be 22 mL

Explanation:

For this problem, we will use the dilution equation:

C1*V1 = C2*V2

<u>Step 1</u>: Data given

with C1 = the initial concentration C1 = 0.220 mg/L

with V1 = the initial volume = 10 mL = 10 * 10^-3 L

with C2 = the final concentration = 0.100 mg/L

with V2 = the final volume = TO BE DETERMINED

<u>Step 2</u>: Calculating the final volume

C1*V1 = C2*V2

0.220 mg/L * 10*10^-3 L = 0.100 mg/L * V2

V2 = (0.220 mg/L * 10*10^-3 L) / 0.100 mg/L

V2 =0.022 L = 22 mL

The final volume should be 22 mL

3 0
4 years ago
I need help ASAP!
MaRussiya [10]
Calcium reacts gently with water to give hydrogen and calcium hydroxide, which is only slightly soluble, thus slows down the reaction.

It will be assumed that hydrochloric acid used is a dilute aqueous solution.

However, calcium reacts with hydrochloric acid to give calcium chloride which is readily soluble in water, and hydrogen, being a typical reaction of relatively active metals with acids.
Ca(s) + 2HCl(aq)  -> CaCl2(aq) +H2(g) &uarr; + heat

The clues that it is a chemical reaction could be:
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As silver is below hydrogen in the electrochemical series, it will not be expected to react with dilute hydrocloric acid. (however, it dissolves in oxidizing acid such as nitric acid, but not displacing hydrogen as a product).

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3 years ago
Ethyne gas combusts with oxygen gas according to the following reaction: Calculate the volume, in mL of CO2 produced when 73 g o
Bezzdna [24]

Answer: Volume of CO2 is 89127 mL

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The amount of C2H2 that react allow us to predict the amount of CO2 that will be obtained

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26g/1mol is molar mass of C2H2 and 2/4 is the molar relation between CO2 and C2H2 in this reaction. Canceling units, at the end mol of CO2 are obtained

Now with the moles of CO2 and the ideal gases equation is possible to calculate the volumen occupied by the gas.

PV = RnT where P: pressure, V: volume, R: ideal gas constant, n: moles and T: temperature expressed in K (add 273,15 to °C temperature: 37,4°C + 273,15 = 310,55K)

V= RnT/P

V= \frac{0,08206 atmL/molK . 5,6 mol. 310,55 K}{1,6 atm}  =89,127 L

To express volume in mL multiply the L result by 1000 which equals 89127 mL

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