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Nonamiya [84]
3 years ago
13

For the reaction A (g) → 2 B (g), K = 14.7 at 298 K. What is the value of Q for this reaction at 298 K when ∆G = -20.5 kJ/mol?

Chemistry
1 answer:
harina [27]3 years ago
6 0

Answer:

Q= 245 =2.5 * 10^2

Explanation:

ΔG = ΔGº + RTLnQ, so also ΔGº= - RTLnK

R= 8,314 J/molK, T=298K

ΔGº= - RTLnK = - 6659.3 J/mol = - 6.7 KJ/mol

ΔG = ΔGº + RTLnQ → -20.5KJ/mol = - 6.7 KJ/mol + 2.5KJ/mol* LnQ

→ 5.5 = LnQ → Q= 245 =2.5 * 10^2

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If you feed 100 kg of N2 gas and 100 kg of H2 gas into a<br> reactor. What is the limiting reactant?
mixas84 [53]

Answer:

N₂ is the limiting reactant

Explanation:

The balanced reaction between N₂ gas and H₂ gas is:

N₂ + 3H₂ → 2NH₃

In order to determine the limiting reactant, we have to <u>calculate the number of moles of each rectant</u>, using their molecular weight:

  • Moles of N₂= 100 kg * \frac{1kmol}{28kg} = 3.57 kmol
  • Moles of H₂= 100 kg * \frac{1kmol}{2kg} = 50.0 kmol

Lastly, we multiply the number of moles of N₂ by 3, and the number of moles of H₂ by 1; due to the coefficients in the balanced reaction. Whichever number is lower, belongs to the limiting reactant.

N₂ => 10.7

H₂ => 50.0

Thus N₂ is the limiting reactant

8 0
3 years ago
From data below, calculate the total heat (in J) associated with the conversion of 0.499 mol ethanol gas (C2H6O) at 301°C and 1
8_murik_8 [283]

Answer:

The total heat associated is -30,520.3 J.

Explanation:

Moles of ethanol = 0.499 moles

Molar mass of ethanol = 46 g/mol  

Mass = Moles × Molar mass = 0.499 moles × 46 g/mol = 22.954 g

m is the mass of ethanol = 22.954 g

Q₁ is heat involved in the conversion of 22.954 g ethanol gas at 301°C to ethanol gas at 78.5°C

Thus, Q₁ = m × c × ΔT

Where,  

c =  The specific heat of the gas = 1.43 J/g°C

ΔT = Final temperature - Initial temperature = 78.5 - 301°C  

= - 222.5 °C

Applying the values in the above equation as:-

Q_1 = 22.954 g\times 1.43 J/g^0C\times (-222.5^oC) = -7303.3J

Q₂ is the enthalpy of condensation from gas to liquid for the given mass of ethanol .

Thus, Q₂ = moles×ΔH condensation  

Given that:- ΔH vaporization = 40.5 kJ/mol

Enthalpy of condensation of gaseous ethanol to liquid ethanol = - 40.5 kJ/mol

Considering, 1 kJ = 1000 J

So,  

ΔH condensation = - 40.5 ×1000 J/mol = - 40500 J/mol

Thus, Q₂ = 0.499 moles × (- 40500 J/mol) = -20209.5 J

Q₃ is heat involved in the conversion of 22.954 g gaseous ethanol at 78.5°C to ethanol liquid at 25.0°C.

Thus, Q₃ = m × C ×ΔT

Where,  

C = The specific heat of the liquid = 2.45 J/g°C

ΔT = Final temperature - Initial temperature = 25.0 - 78.5 °C  

= - 53.5 °C

Applying the values in the above equation as:-

Q_3 = 22.954 g\times 2.45 J/g^0C\times (-53.5 ^0C)=-3007.5 J

Applying the values as:

Total heat = Q_1+Q_2+Q_3

= -7303.3 J - 20209.5 J - 3007.5 J

= -30,520.3 J

The total heat associated is -30,520.3 J.

4 0
3 years ago
What is the molar mass of HBR
alexdok [17]

Answer:

Molar mass of bromine is equal to 80.9119

Explanation:

The molar mass of HBr is equal to the sum of atomic weight of  Bromine.

Atomic Weight of hydrogen is equal to 1.00794

Atomic Weight  of Bromine is equal to 79.904

Molar mass of Bromine

= Atomic Weight of hydrogen + Atomic Weight  of Bromine

Molar mass of Bromine  = 79.904 + 1.00794  = 80.9119

3 0
3 years ago
Calculate the volume of 5.00 mol of helium at 120C and 1520 mm Hg
levacccp [35]

Answer:

80.7 L

Step-by-step explanation:

This looks like a case where we can use the Ideal Gas Law to calculate the volume.

pV = nRT       Divide both sides by p

V = (nRT)/p

=====

Data:

n = 5.00 mol

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = (120 +273.15) K = 393.15K

p = 1520 mmHg × 1 atm/760 mmHg = 2.00 atm

=====

Calculation:

V = (5.00 × 0.082 06 × 393.15)/2.00

V = 161.3/2.00

V = 80.7 L  

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3 years ago
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oksian1 [2.3K]

Answer:

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For Filipinos, traditions in their home and in their family are important. They usually set aside a specific day for a certain celebration like festivals, birthday parties, reunions, etc. And of course, every gathering is dedicated to keeping up with each other over sumptuous food.

<h2 /><h2>Filipino love to party</h2>

Yes, Filipinos love to hold celebrations and fiestas. Bacolod has its MassKara Festival, Davao has its Kadayawan Festival, and Marinduque has its Moriones Festival.

<h3 /><h3>Filipinos have the longest Christmas celebrations—ever</h3>

Even as early as August, you can hear Christmas songs and jingles being played in the malls or in the restaurants in the Philippines. The mood becomes festive, with many people shopping and in good spirits. Christmas celebrations last until around the first or second week of January.

<h3>Filipinos take pride in their families</h3>

In the Philippines, it is family first. So whether you are part of the immediate family or you belong to the third or fourth generation, you are treated as a family member. Sometimes, even the closest of friends are considered family, too.

<h3>Filipinos love art and architecture</h3>

Just look at the massive and tall buildings everywhere. Filipinos have a penchant for bringing art and architecture to a whole new level. They love to design creatively, to think intuitively, and have a passion for anything different and unique.

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Filipino people is the number one in Asia that love boxing.

And filipino have own Martail Arts, like Kali and Arnis.

And many filipino play basket ball every day.

Filipino are strong people and i like that.

I hope it help

<h2>#CarryOnLearning USA</h2>
6 0
3 years ago
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