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Darina [25.2K]
3 years ago
12

Hydrochloric acid and sodium hydroxide will reaxt to form which two compounds?

Chemistry
2 answers:
laila [671]3 years ago
5 0
HCl + NaOH = NaCl + H2O. so it will be sodium chloride and water
Alekssandra [29.7K]3 years ago
3 0
HCl + NaOH = NaCl + H2O. so it will be sodium chloride and water

SCIENCE!
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Calculate the work, w, gained or lost by the system when a gas expands from 15 L to 45 L against a constant external pressure of
marta [7]

Answer:

Work done by the system = 4545 J

Explanation:

The expression for the calculation of work done is shown below as:

w=-P\times \Delta V

Where, P is the pressure

\Delta V is the change in volume

From the question,  

\Delta V = 45 - 15 L = 30 L

P = 1.5 atm

w=-1.5\times 30\ atmL

Also, 1 atmL = 101 J

So,  

w=-1.0\times0.75\times 101\ J=-4545\ J (negative sign implies work is done by the system)

<u>Work done by the system = 4545 J</u>

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3 years ago
When may a scientific theory be revised
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Answer:

A theory doesn’t change into a scientific law because of new or better evidence.

Explanation:

A theory will always remain a theory, and i law will remain a law. The reason being that theories and laws may differ on account of newfound countervailing evidence. Remember, theories and laws are very different from hypotheses.

8 0
3 years ago
What is the name of this alkane? mc012-1.jpg
9966 [12]
THe name of this alkane is <span>1-ethyl,3-methylcyclohexane</span>
6 0
3 years ago
The PH of a 0.1 M MCl (M is an unknown cation) was found to be 4.7. Write the net ionic equation for the hydrolysis of M and its
Serggg [28]

Answer:

6.25 X10^{-9} = Ka

Kb= \frac{10^{-14}}{6.25 X10^{-9}}= 1.6X10^{-6}

Explanation:

The ionic equation for the hydrolysis of the cation of the given salt will be:

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The expression for Ka will be:

Ka = \frac{[H^{+}][MOH]}{[M^{+}]}

As given that the concentration of the salt is 0.1 M and pH of solution = 4.7, we can determine the concentration of Hydrogen ions from the pH

pH = -log [H⁺]

[H⁺] = antilog(-pH) = antilog (-4.7) = 2 X 10⁻⁵ M = [MOH]

Let us calculate Ka from this,

Ka = {2.5X10^{-5}X2.5X10^{-5}}{0.1} = 6.25 X10^{-9}

The relation between Ka an Kb is

KaXKb =10⁻¹⁴

Kb= \frac{10^{-14}}{6.25 X10^{-9}}= 1.6X10^{-6}

6 0
3 years ago
¿Cuál es la razón para que los planetas y los electrones no abandonen sus órbitas saliendo expulsados sin regreso?
bazaltina [42]

Answer:

I wish I could speak Spanish

Explanation:

4 0
3 years ago
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