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3 years ago

A pitcher exerts a force on a baseball that is 30 times the balls weight. How fast is the pitcher accelerating the ball?

Physics

1 answer:

iVinArrow [24]3 years ago

8 0

Answer:

Pitcher is accelerating the ball at 30 times of acceleration due to gravity = 294 m/s²

Explanation:

Force applied on baseball = 30 times weight of the ball.

Weight of ball = mg, where m is the mass of ball and g is acceleration due to gravity value.

We have force applied is also equal to product of mass and acceleration.

F = ma = 30 x mg

a = 30g

So, pitcher is accelerating the ball at 30 times of acceleration due to gravity = 294 m/s²

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2 years ago

An object has 90,000 J of kinetic energy and is moving at 12 m/s. What is the objects mass?

trapecia [35]

Answer:

plug it into your calculator

Explanation:

Kinetic energy = KE = Joules = J

KE= 1/2mv^2

90,000 = 1/2 m (12^2)

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3 years ago

A person's center of mass is very near the hips, at the top of the legs. Model a person as a particle of mass mm at the top of a

muminat

Answer:

$\mathbf{v_{max} = \sqrt{gL}}$

Explanation:

Considering an object that moving about in a circular path, the equation for such centripetal force can be computed as:

$\mathbf {F = \dfrac{mv^2}{2}}$

The model for the person can be seen in the diagram attached below.

So, along the horizontal axis, the net force that is exerted on the person is:

$mg cos \theta = \dfrac{mv^2}{L}$

Dividing both sides by "m"; we have :

$g cos \theta = \dfrac{v^2}{L}$

Making "v" the subject of the formula: we have:

$v^2 = g Lcos \theta$

$v=\sqrt{ gL cos \theta$

So, when $\theta$ = 0; the velocity is maximum

∴

$v_{max} = \sqrt{gL \ cos \theta}$

$v_{max} = \sqrt{gL \ cos (0)}$

$v_{max} = \sqrt{gL \times 1}$

$\mathbf{v_{max} = \sqrt{gL}}$

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2 years ago

25 points!

pentagon [3]

Answer:

Explanation:

Given parameters:

Mass of object = 6kg

Initial velocity = 5m/s

Final velocity = 25m/s

Time = 30s

Unknown:

Net force acting on the object = ?

Solution:

From Newton's second law of motion:

Force = mass x acceleration

Acceleration is the rate of change of velocity with time

Acceleration = $\frac{Final velocity - Initial velocity }{time}$

Force = mass x $\frac{Final velocity - Initial velocity }{time}$

So;

Force = 6 x $\frac{25 - 5}{30}$ = 6N

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The surface of the rock eroded

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