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3 years ago

A pitcher exerts a force on a baseball that is 30 times the balls weight. How fast is the pitcher accelerating the ball?

Physics

1 answer:

iVinArrow [24]3 years ago

8 0

Answer:

Pitcher is accelerating the ball at 30 times of acceleration due to gravity = 294 m/s²

Explanation:

Force applied on baseball = 30 times weight of the ball.

Weight of ball = mg, where m is the mass of ball and g is acceleration due to gravity value.

We have force applied is also equal to product of mass and acceleration.

F = ma = 30 x mg

a = 30g

So, pitcher is accelerating the ball at 30 times of acceleration due to gravity = 294 m/s²

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grigory [225]

Answer: $h=160.84 W/m^2-K$

Explanation:

Given

mass flow rate=0.3 kg/s

diameter of pipe=5 cm

length of pipe=10 m

Inside temperature=22

Pipe surface =100

Temperature drop=30

specific heat of vapor(c)=2190 J/kg.k

heat supplied $Q=mc\Delta T=0.3\times 2190\times (30)$

Heat due to convection =hA(100-30)

$A=\pi d\cdot L$

$A=\pi 0.05\times 10=1.571 m^2$

$Q_{convection}=h\times 1.571\times (100-22)=122.538 h$

$Q=Q_{convection}$

19,710=122.538 h

$h=160.84 W/m^2-K$

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2 years ago

Each of the two coils has 320 turns. The average radius of the coil is 6 cm. The distance from the center of one coil to the ele

Temka [501]

Answer:

Magnetic field, $B=2.39\times 10^{-3}\ T$

Explanation:

It is given that,

Number of turns, N = 320

Radius of the coil, r = 6 cm = 0.06 m

The distance from the center of one coil to the electron beam is 3 cm, x = 3 cm = 0.03 m

Current flowing through the coils, I = 0.5 A

We need to find the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils. The magnetic field midway between the coils is given by :

$B=\dfrac{\mu_oINr^2}{(x^2+r^2)^{3/2}}$

$B=\dfrac{4\pi \times 10^{-7}\times 0.5\times 320\times (0.06)^2}{(0.03^2+0.06^2)^{3/2}}$

B = 0.00239 T

$B=2.39\times 10^{-3}\ T$

So, the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils is $2.39\times 10^{-3}\ T$ . Hence, this is the required solution.

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3 years ago

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Julli [10]

Answer:

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Explanation:

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3 years ago

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Answer:

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2 years ago

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Answer:

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Explanation:

if correct plzz brainliest :D

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2 years ago

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