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Dahasolnce [82]
3 years ago
7

When you jump from an elevated position you usually bend your knees upon reaching the ground, which makes the time of the contac

t about 10 times that of a stiff-legged landing. In this way the average force your body experiences is Group of answer choices about 10 times as great. more than 1/10 as great. about 1/10 as great. less than 1/10 as great.
Physics
1 answer:
masya89 [10]3 years ago
5 0

Answer:

The correct option is c. about 1/10 as great

Explanation:

The problem can be understood by the concept of impulse. Impulse is a integral of force.

                                  Impulse = Force × Time

As when we bend our knees upon reaching the ground the time of contact is about 10 times that of a stiff-legged. so,

                                 (Time)_{bend} = 10 × Time

So the force will be:

                                Force = \frac{Impulse}{(Time)_{bend} }

                                Force = \frac{Impulse}{10* Time}

                                Force = \frac{1}{10} × \frac{Impulse}{Time}

Hence the force is one tenth of the total as seen by the calculation.

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vredina [299]

1) The final velocity of the two trains is 6 m/s to the right

2) It is an inelastic collision

Explanation:

1)

We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the two trains must be conserved before and after the collision.

Therefore we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 = 6,000 kg is the mass of the first train

u_1 = 10 m/s is the initial velocity of the first train

m_2 = 4,000 kg is the mass of the second train

u_2 = 0 is the initial velocity of the second train  (initially at rest)

v is the final combined velocity of the two trains

Solving the equation for v, we find the final velocity of the two trains:

v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{(6000)(10)+0}{6000+4000}=6 m/s

2)

There are two types of collisions:

  • Elastic collision: in an elastic collision, both the total momentum and the total kinetic energy of the system are conserved
  • Inelastic collision: in an inelastic collision, only the total momentum is conserved, while the total kinetic energy is not (part of it is converted into thermal energy due to internal frictions)

To verify what type of collision is this, we can compare the total kinetic energy before and after the collision:

Before:

K=\frac{1}{2}m_1 u_1^2 = \frac{1}{2}(6000)(10)^2=300,000 J

After:

K=\frac{1}{2}(m_1 +m_2)v^2 = \frac{1}{2}(6000+4000)(6)^2=180,000 J

As we can see, the kinetic energy is not conserved, so this is an inelastic collision.

Learn more about momentum here:

brainly.com/question/7973509  

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3 years ago
An example of an object in projectile motion is
Usimov [2.4K]

Answer: a. a leaping frog

Explanation: In a projectile motion the object must have a certain path or trajectory with respect to a certain angle. For the leaping frog its velocity can be resolve into components having the final velocity at the highest point to be zero.

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3 years ago
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the diagram below shows the situation described in the problem. the focal length of the lens is labeled f; the scale on the opti
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2 years ago
A mechanic has a wrench where the hand grip is 0.40 m from the axis of the bolt. To apply a torque of 170 N m with this wrench w
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Answer:

4.3 * 10 N

Explanation:

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Explanation:

its either a or d however i say the best choice is d

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