Answer:
Space mean speed = 44 mi/h
Explanation:
Using Greenshield's linear model
q = Uf ( D - /Dj )
qcap = capacity flow that gives Dcap
Dcap = Dj/2
qcap = Uf. Dj/4
Where
U = space mean speed
Uf = free flow speed
D = density
Dj = jam density
now,
Dj = 4 × 3300/55
= 240v/h
q = Dj ( U - /Uf)
2100 = 240 ( U - /55)
Solve for U
U = 44m/h
Answer:
And replacing in the Carnot efficiency we got:
Explanation:
For this case we can use the fact that the maximum thermal efficiency for a heat engine between two temperatures are given by the Carnot efficiency:
We have on this case after convert the temperatures in kelvin this:
And replacing in the Carnot efficiency we got:
And the maximum power output on this case would be defined as:
Where represent the heat associated to the deposit with higher temperature.
Answer:
battery life in year = 9 years and 48 days
Explanation:
given data
Battery Ampere-hours = 1.5
Pulse voltage = 2 V
Pulse width = 1.5 m sec
Pulse time period = 1 sec
Electrode heart resistance = 150 Ω
Current drain on the battery = 1.25 µA
to find out
battery life in years
solution
we get first here duty cycle that is express as
duty cycle = ...............1
duty cycle = 1.5 ×
and applied voltage will be
applied voltage = duty energy × voltage ...........2
applied voltage = 1.5 × × 2
applied voltage = 3 mV
so current will be
current = ................3
current =
current = 20 µA
so net current will be
net current = 20 - 1.25
net current = 18.75 µA
so battery life will be
battery life =
battery life = 80000 hours
battery life in year =
battery life in year = 9.13 years
battery life in year = 9 years and 48 days