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4 years ago

Does a car speedometer measure speed, velocity, or both?explain

Physics

1 answer:

Crank4 years ago

7 0

Answer:

Car speedometer only measures speed and doesn't give any information about direction. So yes to speed, no to velocity.

You might be interested in

The mass of an object is 45 kilograms. its weight on earth is what?

Kitty [74]

Weight = 45 * 9.8 = 441 N

4 0

4 years ago

A child with a weight of 230 N swings on a playground swing attached to 1.90 m long chains. What is the gravitational potential

nlexa [21]

Answer:

437 J

Explanation:

Parameters given:

Weight of child, W = 230 N

Height of swing, h = 1.9 m

Gravitational Potential Energy is given as:

P. E. = m*g*h = W*h

m = mass

h = height above the ground

W = weight

P. E. = 230 * 1.9

P. E. = 437 J

7 0

3 years ago

Read 2 more answers

Một mặt phẳng vô hạn tích điện đều, mật độ σ = 4.10-9 C/cm2, đặt thẳng đứng trong không khí. Một quả cầu nhỏ có khối lượng 8 g,

dusya [7]

Answer:

The angle is 18.3 degree.

Explanation:

A uniformly charged infinite plane, density σ = 4 x 10^-9 C/cm^2, is placed vertically in air. A small ball of mass 8 g, with charge q = 10^-8 C, hangs close to the plane, so that the string is initially parallel to the plane. Take g = 9.8m/s2. When in equilibrium, by what angle is the string hanging the ball to the plane?

surface charge density, σ = 4 x 10^-5 C/m^2

Charge, q = 10^-8 C

mass, m = 0.008 kg

Let the angle is A and the tension in the string is T.

The electric field due to a plane is

$E =\frac{\varepsilon \sigma }{2\varepsilon o}\\\\E =\frac{4\times 10^{-5}}{2\times 8.85\times 10^{-12}}\\\\E = 2.26\times 10^6 V/m \\$

Now equate the forces,

$T sin A = q E.... (1)\\\\T cos A = m g ..... (2)\\\\divide (1) by (2)\\\\tan A = \frac{10^{-8}\times 2.6\times 10^6}{0.008\times 9.8}\\\\tan A = 0.33\\\\ A = 18.3 degree$

5 0

3 years ago

What is the magnitude of your displacement when you follow directions that tell you to walk 225 m in one direction, make a 90° t

Gekata [30.6K]

Start by facing East. Your first displacement is the vector

d₁ = (225 m) i

Turning 90º to the left makes you face North, and walking 350 m in this direction gives the second displacement,

d₂ = (350 m) j

Turning 30º to the right would have you making an angle of 60º North of East, so that walking 125 m gives the third displacement,

d₃ = (125 m) (cos(60º) i + sin(60º) j )

d₃ ≈ (62.5 m) i + (108.25 m) j

The net displacement is

d = d₁ + d₂ + d₃

d ≈ (287.5 m) i + (458.25 m) j

and its magnitude is

|| d || = √[ (287.5 m)² + (458.25 m)² ] ≈ 540.973 m ≈ 541 m

7 0

3 years ago

A light wave with an electric field amplitude of E0 and a phase constant of zero is to be combined with one of the following wav

Anarel [89]

Answer:

the greatest intensity is obtained from c

Explanation:

An electromagnetic wave stagnant by the expression

E = E₀ sin (kx -wt)

when two waves meet their electric fields add up

E_total = E₁ + E₂

the intensity is

I = E_total . E_total

I = E₁² + E₂² + 2E₁ E₂ cos θ

where θ is the phase angle between the two rays

Let's examine the two waves

in this case E₁ = E₂ = E₀

I = Eo2 + Eo2 + 2 E₀ E₀ coasts

I = E₀² (2 + 2 cos θ )

I = 2 I₀ (1 + cos θ )

let's apply this expression to different cases

a) In this case the angle is zero therefore the cosine is worth 1 and the intensity is I_total = 4 I₀

b) cos π = -1 this implies that I_total = 0

c) the cosine is 1,

I = E₀² + 4E₀² + 2 E₀ (2E₀) cos θ

I = E₀² (5 +4 cos θ)

I = E₀² 9

I = 9 Io

d) in this case the cos pi = -1

I = E₀² (5 -4)

I = I₀

e) we rewrite the equation

I = E₀² + 9 E₀² + 2 E₀ (3E₀) cos θ

I = Eo2 (10 + 6 cos θ)

cos π = -1

I = E₀² (10-6)

I = 4 I₀

the greatest intensity is obtained from c

3 0

3 years ago