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Tems11 [23]
3 years ago
7

The image shows street lights powered by solar panels. Which sequence shows the energy transformations taking place in these lig

hts?
Physics
2 answers:
yawa3891 [41]3 years ago
8 0

the answer is C. for plato

katrin [286]3 years ago
8 0

Answer:

The image is missing, but let's explain the process here:

The energy comes from the sun and is absorbed by the solar panels (that absorb the light energy) and is stored as chemical energy into batteries, then this battery transforms the chemical energy into electrical energy, which is the one that supplies the light bulbs, creating light energy again.

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A woman is running around a playground while keeping an eye on her child who is on a swing set. The child is going back and fort
Nutka1998 [239]

Answer:

(a) 1500 m

(b) 2827.43m

Explanation:

Given that the time for one cycle of the swing is 1 s

The radius of the swing, R= 3.0m

The angle covered, \theta, by each swing is a quarter of the circle. i.e.

\Theta=\frac {\pi}{2}

Speed of running of women =5 m/s.

Time of running = 5 minutes= 5 x 60 secondes= 300 s.

(a) As distance= (speed) x (time)

So, the required distance= 5 x 300 m= 1500 m.

(b) As there are two swings in one cycle, so, the distance covered in one swing is the length of the circular shown in the figure.

As arc length, l= \theta R, where \theta is the angle, in radian, subtended by the arc at the center, and R is the radius of curvature of the arc.

So, the distance covered by the child in 1 swing = \frac {\pi}{2}\times 3 m=\frac{3\pi}{2}m.

In 1 cycle, there are 2 swings, so distance covered in 1 cycle = 3 \pi m.

Now, in 1 second there is 1 cycle, so in 5 minutes there will be 300 cycles.

So, the total distance covered by the child

= 3\pi\times 300 m= 2827.43 m.

3 0
3 years ago
What best describes an impulse acting on an object
Elena-2011 [213]
It's sort of like force so say you said dog then you used like force or impulse
4 0
3 years ago
Suppose that an electromagnetic wave which is linearly polarized along the x−axis is propagating in vacuum along the z−axis. The
goldfiish [28.3K]
I think the answer to your question is B
7 0
3 years ago
How much would a 70.0-kg person weigh on Mercury?
Natalija [7]

As weight =w =mg

g= gravitational acceleration on mercury = 3.7m/sec2

Mass of person =m= 70 kg

So w =(70kg)(3.7m/sec2)

w= 259 kgm/sec2

W= 259 N

6 0
3 years ago
Replacing an object attached to a spring with an object having 14 the original mass will change the frequency of oscillation of
Pachacha [2.7K]

Answer:

<em>The frequency changes by a factor of  0.27.</em>

<em></em>

Explanation:

The frequency of an object with mass m attached to a spring is given as

f = \frac{1}{2\pi } \sqrt{\frac{k}{m} }

where f is the frequency

k is the spring constant of the spring

m is the mass of the substance on the spring.

If the mass of the system is increased by 14 means the new frequency becomes

f_{n} = \frac{1}{2\pi } \sqrt{\frac{k}{14m} }

simplifying, we have

f_{n} = \frac{1}{2\pi \sqrt{14} } \sqrt{\frac{k}{m} }

f_{n} = \frac{1}{3.742*2\pi  } \sqrt{\frac{k}{m} }

if we divide this final frequency by the original frequency, we'll have

==> \frac{1}{3.742*2\pi  } \sqrt{\frac{k}{m} }  ÷  \frac{1}{2\pi } \sqrt{\frac{k}{m} }

==> \frac{1}{3.742*2\pi  } \sqrt{\frac{k}{m} }  x  2\pi \sqrt{\frac{m}{k} }

==> 1/3.742 = <em>0.27</em>

7 0
3 years ago
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