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sweet-ann [11.9K]
3 years ago
15

Block 1 and block 2 have the same mass,m, and are released from the top of two inclined planes of the same height making 30° and

60° angles with the horizontal direction, respectively. If the coefficient of friction is the same in both cases, which of the blocks is going faster when it reaches the bottom of its respective incline?
Physics
1 answer:
Sidana [21]3 years ago
5 0

Answer: The mass released from the top of the 60º incline.

 

Explanation:

The external forces acting upon any of the masses, are the same for both (not numerically): the gravity, the normal force and the friction force.

As the gravity is always directed downward, we can decompose it in a component normal to the surface (that is equal to the normal force as the body is not accelerating in this direction), and another which is parallel to the incline, and which is the responsible for the acceleration of the object along the incline (opposed by the friction force).

So, we can write the following:

Fx = mg sin θ - μk .Fn = m.g. sin θ - μk. mg cos θ= m a

We can easily see, that if the angle is larger, the acceleration component due to gravity will be larger, and at the same time, the friction force will be smaller, so the acceleration for the 60º will be the larger one.

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vector u has a magnitude of 20 and direction of 0°.vector v has amagnitude of 40and a direction of 60°.find the magnitude and di
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Addition of vectors:

vector u

has a magnitude of 20 and a direction of 0º with respect to the horizontal, vector v has a magnitude of 40 and a direction of 60º with respect to the horizontal.

a) Find the magnitude and direction of the resultant to the nearest whole

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Vector Sum:

The resultant of two vectors is simply the vector sum of the vectors. There are a handful of ways to present the resultant factor; the notation that shows the vector magnitude and direction is called the polar vector notation. An example of a vector presented in polar vector notation is

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Answer and Explanation:

Let's first present the vectors in rectangular vector notation.

For the vector →u of magnitude 20 and direction 0∘ to the horizontal axis, the vector is →u=^i20.

For the vector →v

of magnitude 40 and direction 60∘ to the horizontal axis, the vector is →v=^i40cos60∘+^j40sin60∘.

The resultant vector →w is the vector sum of the vectors, i.e.

→w=→u+→v

=^i20+^i40cos60∘+^j40sin60∘

=^i(20+40cos60∘)+^j(40sin60∘)

=^i40+^j20√3

For a vector ^ix+^jy, the magnitude of the vector is √x2+y2 and the direction above the horizontal axis is θ=tan−1(yx).

Let's use the formulas:

|→w|∠θ=√(40)2+(20√3)2∠tan−1(20√340)≈52.9∠40.9∘

The magnitude of the vector is about 53 units in the direction 41-degrees above the horizontal axis.

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