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morpeh [17]
3 years ago
10

Digital thermometers often make use of thermistors, a type of resistor with resistance that varies with temperature more than st

andard resistors. Find the temperature coefficient of resistivity (in (°C)−1) for a linear thermistor with resistances of 80.2 Ω at 0.00°C and 224 Ω at 522°C.
Physics
1 answer:
elena-14-01-66 [18.8K]3 years ago
8 0

Answer:

0.0034^oC^{-1}

Explanation:

The temperature coefficient (α) of the resistor can be calculated as follows:

R =R_o[1+\alpha(T-T_o)]

Where, R is the resistance at temperature T, R_o is the resistance at temperature T_o

Substitute the values:

224\Omega=80.2\Omega[1+\alpha(522^o C-0^oC)]\\ \Rightarrow \alpha = \frac{2.8-1}{522} = 0.0034^oC^{-1}

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Here,

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PART B) The period of satellite is given as,

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T = \frac{2\pi (2*6370*10^3)}{5.591*10^3}

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4 years ago
PLEASE HELP!!!!!!! MT TIME FOR MY TEST IS ALMOST OVER!!!
pav-90 [236]

Answer:

50 N

Explanation:

Let the natural length of the spring = L

so

100 = k(40 - L)       (1)

200 = k(60 - L)       (2)

(2)/(1):   2 = (60 - L)/(40 - L)

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2L - L = 80 - 60

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2 years ago
Imagine Two Artificial Satellites Orbiting Earth At The Same Distance. One Satellite Has A Greater Mass Than The Other One? Whic
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After reading this whole question, I feel like I've already
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If you increase the voltage in the circuit where that resistor is
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