Question

Digital thermometers often make use of thermistors, a type of resistor with resistance that varies with temperature more than standard resistors. Find the temperature coefficient of resistivity (in (°C)−1) for a linear thermistor with resistances of 80.2 Ω at 0.00°C and 224 Ω at 522°C.

Answer 1

Answer:

$0.0034^oC^{-1}$

Explanation:

The temperature coefficient (α) of the resistor can be calculated as follows:

$R =R_o[1+\alpha(T-T_o)]$

Where, R is the resistance at temperature T, $R_o$ is the resistance at temperature $T_o$

Substitute the values:

$224\Omega=80.2\Omega[1+\alpha(522^o C-0^oC)]\\ \Rightarrow \alpha = \frac{2.8-1}{522} = 0.0034^oC^{-1}$