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love history [14]
3 years ago
9

Which group of elements is considered the most reactive non-metals?

Chemistry
2 answers:
Eva8 [605]3 years ago
6 0
<h2>Question:</h2>

Which group of elements is considered the most reactive non-metals?

<h2>Answer:</h2>

<u>D</u><u>.</u><u> </u><u>Noble</u><u> </u><u>Gases</u><u> </u>

  • <u>Th</u><u>e </u><u>noble</u><u> </u><u>gasses</u><u> </u><u>are a special group because of their lack of reactivity, the element fluorine is the most reactive nonmetal. It is not found in nature as a free element.</u>

<h2><u>#CARRYONLEARNING</u><u> </u></h2><h2><u>#STUDYWELL</u><u> </u></h2>
Lina20 [59]3 years ago
3 0
The answer would be C. Halogens. Noble gases are NON reactive and the others are less reactive. Halogens are the most reactive non metals.
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Will xenon react to nitrogen and why?
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7 0
4 years ago
Which of the following would absorb the most sunlight?
MrRa [10]
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6 0
3 years ago
Acetic acid (CH 3 COOH) reacts with water to form the acetate ion and the hydronium ion: CH 3 COOH(aq)+H 2 O(l) leftrightarrow C
Bezzdna [24]

Answer: 1.8 * 10 ^ -5

Explanation:

3 0
3 years ago
Air is a mixture of gases that is about 78.0% n2 by volume. when air is at standard pressure and 25.0 ∘c, the n2 component will
ArbitrLikvidat [17]

Step first:

Since, 78.0 percent  N_{2} by volume is present in the air which implies there are 78 moles of N_{2} present in 100 moles of air.

Now,

Mole fraction of N_{2} = \frac{Moles of N_{2}}{Total moles of gases in the mixture}

Mole fraction  =\frac{78}{100} mol

= 0.78

Partial pressure is equal to the multiplication of total pressure and mole fraction.

Partial pressure = 0.78\times 1 atm (as 1 atm is atmospheric pressure)

= 0.78 atm.

Step second:

Henry's law constant is calculated by:

S_{g}=k\times P_{g}

where,

S_{g} is solubility of gas

P_{g} is partial pressure of gas

k is henry's law constant

Substitute the value of solubility and partial pressure to find the value of Henry's law constant in above formula:

4.88\times 10^{-4} M=k\times 0.78 atm

k = \frac{4.88\times 10^{-4}M}{0.78 atm}

= 6.25\times 10^{-4} M atm^{-1}

Thus, Henry's Law constant is 6.25\times 10^{-4} mol L^{-1} atm^{-1}.




5 0
3 years ago
Read 2 more answers
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