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never [62]
1 year ago
11

Nutritional biochemists have known for decades that acidic foods cooked in cast-iron cookware can supply significant amounts of

dietary iron (ferrous ion).
(b) Measurements show an increase from 3.3 mg of iron to 49 mg of iron per (1/2)-cup (125-g) serving during the slow preparation of tomato sauce in a cast-iron pot. How many ferrous ions are present in a 26-oz (737-g) jar of the tomato sauce?
Chemistry
1 answer:
podryga [215]1 year ago
4 0

The number of ferrous ions present in jar are 3.1x 10^21.

<h3>Steps</h3>

Since we have 737 g, 5,896 servings are generated.

If one serving contains 49 mg of iron, then one can contains 49*5,896 mg of iron.

In other words, if made in a cast-iron pot, one jar of tomato sauce has 288,9 mg of iron.

The number of ferrous ions present in jar are 3.1x 10^21.

<h3>What exactly does nutritional biochemistry mean?</h3>

Nutritional biochemistry is the study of nutrition as a science that deals with physiology, medicine, microbiology, pharmacology, chemistry, and biology and uses these sciences for the investigation of health, diet, and nutrition as well as the research of disease and the administration of medications.

<h3>What does nutritional biochemistry teach you?</h3>

This covers a fundamental knowledge of molecular genetics, biostatistics, epidemiology, and metabolism. Learn the laboratory skills necessary for current biochemical and molecular investigations into diet and its impact on health and illness.

learn more about biochemist here

brainly.com/question/2256082

#SPJ4

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If 16 moles of al react with 3 moles of S8 how many moles of Al2 S3 will be formed
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8 moles

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CaBr + KOH – Ca(OH), + KBr (balance first) What mass, in grams, of
neonofarm [45]

Answer:

129.73 g of CaBr₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

CaBr₂ + 2KOH –> Ca(OH)₂ + 2KBr

Next, we shall determine the mass of CaBr₂ that reacted and the mass of Ca(OH)₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of CaBr₂ = 40 + (80×2)

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SUMMARY :

From the balanced equation above,

200 g of CaBr₂ reacted to produce 74 g of Ca(OH)₂.

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From the balanced equation above,

200 g of CaBr₂ reacted to produce 74 g of Ca(OH)₂.

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Xg of CaBr₂ = (200 × 48)/74

Xg of CaBr₂ = 129.73 g

Thus, 129.73 g of CaBr₂ were consumed.

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3 years ago
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