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mina [271]
3 years ago
13

Consider a CMOS inverter which has ideal transistors with the following characteristics: PMOS transistor: W/L = 2; Mobility (up)

= 72cm/V*s; threshold voltage = -0.4V nMOS transistor: W/L = 1; Mobility(un)= 180cmP/V*s; threshold voltage = 0.4V 180nm process; gate oxide capacitance/unit area = 8.6e-7 F/cm²; Vpp = 1.8V a) Calculate the B for each transistor, including the unites (3 points) b) What modes of operation is each transistor in when Vin=OV, 0.9V, and 1.8V? (3 points) c) Estimate the current through the inverter if Vin=0.9V. List any assumptions you make. (8 points) d) Would you expect the current to be higher or lower if the inverter was implemented in a 130nm process? Explain your answer. (6 points)
Engineering
1 answer:
yaroslaw [1]3 years ago
6 0

Answer:

The transistor will be in amplifier mode and we will expect current will be higher than expected.

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no artical shoul be used here

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3 years ago
A horizontal rigid bar ABC is pinned at end A and supported by two cables at points B and C. A vertical load P 5 10 kN acts at e
BARSIC [14]

Answer:

vertical load = 10 kN

Modulus of elasticity = 200GPa

Yield stress on the cable = 400 MPa

Safety factor = 2.0

Explanation:

Data

let L = \sqrt{(1.5)^{2} + (1.5)^{2} }

        = 3.35 m

substituting 1.5 m for h and 3 m for the tern (a + b)

\theta = tan⁻¹(\frac{1.5}{1.5})

  = 45⁰

substituting 1.5 for h and 3 m for (a+ b) yields:

\theta₂ = tan⁻¹ (\frac{1}{3})

   =25.56⁰

checking all the forces, they add up to zero. This means that the system is balanced and there is no resultant force.

6 0
3 years ago
A vehicle of 1 200 kg is moving at a speed of 40 km/h on an incline of 1 in 50. The total constant rolling and wind resistance i
Readme [11.4K]

Answer:11.602 KW

Explanation:

mass of vehicle\left ( m\right )=1200 kg

speed=40Km/h

Resistance=600 N

\eta =80%

Gear ratio\left ( G\right )=4:1

D_{effective}=500mm

Net force to overcome by engine is

F=Resistance + sin component of weight

F=600+mgsin\theta

Where tan\theta =[tex]\frac{1}{50}

\theta =1.1457^{\circ}

F=600+1200\times 9.81\times sin\left ( 1.1457\right )

F=600+235.38=835.38 N

power=F.v=835.38\frac{100}{9}

Engine Power=\frac{835.\frac{100}{9}}{\eta }=11.602 KW

4 0
4 years ago
John has an exhaust leak in his Acura Integra GS-R, What steps would he take to fix the leak in time for his inspection?
SCORPION-xisa [38]

Answer:

Explanation:

Fist you need to identify where the leak is coming from. You can do this by either listening for the leak or spraying soapy water on the exhaust to look for air bubbles coming out of the exhaust. Depending on the spot of the leak there are many ways you can fix this leak.

1. Exhaust clamp

2. Exhaust putty

3. Exhaust tape

4. New exhaust

Exhaust clamp is best used for holes on straight pipes.

Putty is best used on welds or small holes like on exhaust manifolds or welds connecting various pieces like catalytic converters, mufflers, or resonators.

Tape will work best on straight pipes with holes.

New exhaust is for when the thig is beyond repair, like rust.

Now good luck because working on exhausts is a pain.

4 0
2 years ago
What is the purpose of a weld symbol
andreev551 [17]

Answer:

To indicate the welding or cutting processes

8 0
3 years ago
Read 2 more answers
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