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mina [271]
3 years ago
13

Consider a CMOS inverter which has ideal transistors with the following characteristics: PMOS transistor: W/L = 2; Mobility (up)

= 72cm/V*s; threshold voltage = -0.4V nMOS transistor: W/L = 1; Mobility(un)= 180cmP/V*s; threshold voltage = 0.4V 180nm process; gate oxide capacitance/unit area = 8.6e-7 F/cm²; Vpp = 1.8V a) Calculate the B for each transistor, including the unites (3 points) b) What modes of operation is each transistor in when Vin=OV, 0.9V, and 1.8V? (3 points) c) Estimate the current through the inverter if Vin=0.9V. List any assumptions you make. (8 points) d) Would you expect the current to be higher or lower if the inverter was implemented in a 130nm process? Explain your answer. (6 points)
Engineering
1 answer:
yaroslaw [1]3 years ago
6 0

Answer:

The transistor will be in amplifier mode and we will expect current will be higher than expected.

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Write a program that removes all spaces from the given input. You may assume that the input string will not exceed 50 characters
GrogVix [38]

Answer:

Program that removes all spaces from the given input

Explanation:

// An efficient Java program to remove all spaces  

// from a string  

class GFG  

{  

 

// Function to remove all spaces  

// from a given string  

static int removeSpaces(char []str)  

{  

   // To keep track of non-space character count  

   int count = 0;  

 

   // Traverse the given string.  

   // If current character  

   // is not space, then place  

   // it at index 'count++'  

   for (int i = 0; i<str.length; i++)  

       if (str[i] != ' ')  

           str[count++] = str[i]; // here count is  

                                   // incremented  

         

   return count;  

}  

 

// Driver code  

public static void main(String[] args)  

{  

   char str[] = "g eeks for ge eeks ".toCharArray();  

   int i = removeSpaces(str);  

   System.out.println(String.valueOf(str).subSequence(0, i));  

}  

}  

5 0
3 years ago
Read 2 more answers
Write a program that prompts the user to enter time in 12-hour notation. The program then outputs the time in 24-hour notation.
Juliette [100K]

Answer:

THE CODE FOR THE PROGRAM IS GIVEN BELOW:

#include <iostream>

#include "ConvertTimeHeader.h"

using namespace std;

int main()

{

convertTime convert;

int hr, mn, sc = 0;

 

cout << "Please input hours in 12 hr notation: ";

cin >> hr;

cout << "Please input minutes: ";

cin >> mn;

cout << "Please input seconds: ";

cin >> sc;

 

convert.invalidHr(hr);

convert.invalidMin(mn);

convert.invalidSec(sc);

convert.printMilTime();

 

system("Pause");

 

return 0;  

 

}

#include <iostream>

#include "ConvertTimeHeader.h"

using namespace std;

int convertTime::invalidHr (int hour)

{

try{

 if (hour < 13 && hour > 0)

  {hour = hour + 12;

  return hour;}

 else{

 

  cin.clear();

  cin.ignore();

  cout << "Invalid input! Please input hour again in correct 12 hour format: ";

  cin >> hour;

  invalidHr(hour);

  throw 10;

 }

   

}

catch (int c) { cout << "Invalid hour input!";}

}

int convertTime::invalidMin (int min)

{

try{

 if (min < 60 && min > 0)

  {return min;}

 else{

 

  cin.clear();

  cin.ignore();

  cout << "Invalid input! Please input minutes again in correct 12 hour format: ";

  cin >> min;

  invalidMin(min);

  throw 20;

  return 0;

 }

   

}

catch (int e) { cout << "Invalid minute input!" << endl;}

}

int convertTime::invalidSec(int sec)

{

try{

 if (sec < 60 && sec > 0)

  {return sec;}

 else{

 

  cin.clear();

  cin.ignore();

  cout << "Invalid input! Please input seconds again in correct 12 hour format: ";

  cin >> sec;

  invalidSec(sec);

  throw 30;

  return 0;

 }

   

}

catch (int t) { cout << "Invalid second input!" << endl;}

}

void convertTime::printMilTime()

{

cout << "Your time converted: " << hour << ":" << min << ":" << sec;

}

Explanation:

4 0
3 years ago
Casein, a dairy product used in making cheese, contains 25% moisture when wet. A dairy sells this product for $40/100 kg. If req
Nataly_w [17]

Based on the percent moisture content of the dried product, the mass of dried casein produced os 852.3 kg.

<h3>What is the mass of casein in wet casein?</h3>

The mass of casein in 1000 Kg of wet casein is 75% 1000 kg = 750 Kg

Mass of water 250 kg

The mass of casein is constant while the moisture content can be changed.

At 12% moisture content;

750 kg = 88%%

100 % = 100 ×750/88 = 852.27 kg

Therefore, the mass of dried casein produced os 852.3 kg.

Learn more about mass at: brainly.com/question/24658038

#SPJ1

3 0
2 years ago
All the fnaf UNC charecters
astra-53 [7]

Answer:

T.Freddy.

T.Bonnie.

T.Chica.

G.Freddy.

N. Freddy.

F.Foxy.

Mr.Hippo.

R.Freddy.

Explanation:

8 0
2 years ago
Read 2 more answers
A robot was able to detect a burning smell at a shopping mall and prevent a major disaster. Which function enabled the robot to
adelina 88 [10]

Answer:

Smoke detectors on the robot.

Plz rate as Brainliest. I need it to get to the next rank.

3 0
3 years ago
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