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mina [271]
3 years ago
13

Consider a CMOS inverter which has ideal transistors with the following characteristics: PMOS transistor: W/L = 2; Mobility (up)

= 72cm/V*s; threshold voltage = -0.4V nMOS transistor: W/L = 1; Mobility(un)= 180cmP/V*s; threshold voltage = 0.4V 180nm process; gate oxide capacitance/unit area = 8.6e-7 F/cm²; Vpp = 1.8V a) Calculate the B for each transistor, including the unites (3 points) b) What modes of operation is each transistor in when Vin=OV, 0.9V, and 1.8V? (3 points) c) Estimate the current through the inverter if Vin=0.9V. List any assumptions you make. (8 points) d) Would you expect the current to be higher or lower if the inverter was implemented in a 130nm process? Explain your answer. (6 points)
Engineering
1 answer:
yaroslaw [1]3 years ago
6 0

Answer:

The transistor will be in amplifier mode and we will expect current will be higher than expected.

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List five areas that increased energy prices impact.
Effectus [21]

Answer:

Supply, demand, global markets, imports and exports, and government Regulation.

Explanation:

7 0
3 years ago
If you deposit today 11,613 in an account earning 8% compound interest, for how long should you invest the money in order to ear
Elanso [62]
Y = a (b)^t/p

y is total money

a is original amount

b is growth / decay factor

t is time

p is the frequency of every growth or decay

15131.76 = 11613 x 1.08^x

15131.76 / 11613 = 1.08^x

1.303… = 1.08^x

log1.303…. = xlog1.08

x = 3.43902165741 years
3 0
2 years ago
Which of the following is not a function of the cooling system
Pie

Answer:

hola soy dora

Explanation:

5 0
2 years ago
In the fully developed region of flow in a circular pipe, does the velocity profile change in the flow direction?
taurus [48]

Answer:

<em>No, the velocity profile does not change in the flow direction.</em>

Explanation:

In a fluid flow in a circular pipe, the boundary layer thickness increases in the direction of flow, until it reaches the center of the pipe, and fill the whole pipe. If the density, and other properties of the fluid does not change either by heating or cooling of the pipe, <em>then the velocity profile downstream becomes fully developed, and constant, and does not change in the direction of flow.</em>

3 0
3 years ago
Five kilograms of air at 427°C and 600 kPa are contained in a piston–cylinder device. The air expands adiabatically until the pr
son4ous [18]

Answer:

The entropy change of the air is 0.240kJ/kgK

Explanation:

T_{1} =427+273K,T_{1} =700K\\P_{1} =600kPa\\P_{2} =100kPa

T_{2}  is unknown

we can apply the following expression to find T_{2}

-w_{out} =mc_{v} (T_{2} -T_{1} )

T_{2} =T_{1} -\frac{w_{out } }{mc_{v} }

now substitute

T_{2} =700K-\frac{600kJ}{5kg*0.718kJ/kgK} \\T_{2}=533K

To find entropy change of the air we can apply the ideal gas relationship

Δs_{air}=c_{p} ln\frac{T_{2} }{T_{1} } -Rln\frac{P_{2} }{P_{1} }

Δs_{air} =1.005*ln(\frac{533}{700})-0.287* in(\frac{100}{600} )

Δs_{air} =0.240kJ/kgK

4 0
3 years ago
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