Answer:
The work transfer per unit mass is approximately 149.89 kJ
The heat transfer for an adiabatic process = 0
Explanation:
The given information are;
P₁ = 1 atm
T₁ = 70°F = 294.2611 F
P₂ = 5 atm
γ = 1.5
Therefore, we have for adiabatic system under compression

Therefore, we have;

The p·dV work is given as follows;

Therefore, we have;
Taking air as a diatomic gas, we have;

The molar mass of air = 28.97 g/mol
Therefore, we have

The work done per unit mass of gas is therefore;

The work transfer per unit mass ≈ 149.89 kJ
The heat transfer for an adiabatic process = 0.
Answer: B
Explanation: unless newer models added wingding to code inside fused computer...wingdings on a window ...not a motor
Answer:
44.95 tonnes
Explanation:
According to principle of buoyancy the object will just sink when it's weight is more than the weight of the liquid it displaces
It is given that empty weight of box = 40 tons
Let the mass of the stones to be placed be = M tonnes
Thus the combined mass of box and stones = (40+M) tonnes..........(i)
Since the box will displace water equal to it's volume V we have 

Now the weight of water displaced =
is density of water = 1000kg/
Thus weight of liquid displaced =
..................(ii)
Equating i and ii we get
40 + M = 84.95
thus Mass of stones = 44.95 tonnes