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givi [52]
2 years ago
12

24. A laboratory chemist wants to produce 25.0 g NO2 by the following reactions. If the

Chemistry
1 answer:
lyudmila [28]2 years ago
5 0

The amount of N2O5 to start with would be 35.79 grams

<h3>Stoichiometric calculations</h3>

From the balanced equation of the reactions:

2N_2O_5 --- > 4NO_2 + O_2

Mole ratio of N2O5 and NO2 = 1:2

Since the reaction's actual yield is 82%, the theoretical yield would be: 25 x 100/82 = 30.49 grams

Mole of 25 g NO2 = 30.49/46

                              = 0.66 mole

Equivalent mole of N2O5 = 0.54/2 mole

                                               = 0.33 moles

Mass of 0.27 mole N2O5 = 0.33 x 108.01

                                                = 35.79 grams

More on stoichiometric calculations can be found here: brainly.com/question/8062886

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Chromatography is used in purification. Drugs analysts may use the technique to separate the active molecule in a drug molecule, for efficacy or toxicity analysis, from the other drug components.

Explanation:

Chromatography is used to separate a mixture of different components based on the size of their molecules. In liquid chromatography, the mixture is dissolved in a solvent that acts as the mobile phase and then passed along a stationary phase with different kinds of pores, As the mixture passes through the pores, their different components are separated because they take different times to pass through the stationary phase because of their different rates in passing through the pores.

In gas chromatography, a gas is used as a mobile phase while a liquid is used as the stationary phase.

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brainly.com/question/13232854

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6 0
2 years ago
How much heat is absorbed when 63.7 g H2O(l) at 100 degrees Celsius and 101.3kPa is converted to steam at 100
Alona [7]

Answer:

Q = 143,921 J = 143.9 kJ.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the absorbed heat by considering this is a process involving sensible heat associated to the vaporization of water, which is isothermic and isobaric; and thus, the heat of vaporization of water, with a value of about 2259.36 J/g, is used as shown below:

Q=m*\Delta _{vap}H

Thus, we plug in the mass and the aforementioned heat of vaporization of water to obtain the following:

Q=63.7g*2259.36J/g\\\\Q=143,921J=143.9kJ

Regards!

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Ill get back to you on this
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