Question

A group of physics students hypothesize that for an experiment they are performing, the speed of an object sliding down an inclined plane will be given by the expression v=2gd(sin(θ)−μkcos(θ))−−−−−−−−−−−−−−−−−−√. For their experiment, d=0.725meter, θ=45.0∘, μk=0.120, and g=9.80meter/second2. Use your calculator to obtain the value that their hypothesis predicts for v.

Answer 1

Answer:

v = 2.974

Explanation:

Perhaps the formula should be

v = √(2*g*d (sin(θ) - uk*cos(θ) )                    This is a bit easier to read.

v = √(2* 9.80*0.725(0.707 - 0.12*0.707) )   Substitute values. Find 2*g*d

v = √14.21 * (0.707 - 0.0849)                        Figure out Sin(θ) - uk cos(θ)  

v = √14.21 * (0.6222)

v = √8.8422                                                  Take the square root of the value

v = 2.974

Answer 2

Answer:

$v = 2.97 m/s$

Explanation:

As we know that the velocity expression for the given experiment is

$v = \sqrt{2gd(sin\theta - \mu_kcos\theta)}$

now we know that

d = 0.725 m

$\theta = 45 ^o$

$\mu_k = 0.120$

$g = 9.80$

now we have

$v = \sqrt{2(9.80)(0.725)(sin45 - 0.120cos45)}$

$v = 2.97 m/s$