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tresset_1 [31]
3 years ago
13

A group of physics students hypothesize that for an experiment they are performing, the speed of an object sliding down an incli

ned plane will be given by the expression v=2gd(sin(θ)−μkcos(θ))−−−−−−−−−−−−−−−−−−√. For their experiment, d=0.725meter, θ=45.0∘, μk=0.120, and g=9.80meter/second2. Use your calculator to obtain the value that their hypothesis predicts for v.
Physics
2 answers:
goblinko [34]3 years ago
6 0

Answer:

v = 2.974

Explanation:

Perhaps the formula should be

v = √(2*g*d (sin(θ) - uk*cos(θ) )                    This is a bit easier to read.

v = √(2* 9.80*0.725(0.707 - 0.12*0.707) )   Substitute values. Find 2*g*d

v = √14.21 * (0.707 - 0.0849)                        Figure out Sin(θ) - uk cos(θ)  

v = √14.21 * (0.6222)

v = √8.8422                                                  Take the square root of the value

v = 2.974

Tju [1.3M]3 years ago
6 0

Answer:

v = 2.97 m/s

Explanation:

As we know that the velocity expression for the given experiment is

v = \sqrt{2gd(sin\theta - \mu_kcos\theta)}

now we know that

d = 0.725 m

\theta = 45 ^o

\mu_k = 0.120

g = 9.80

now we have

v = \sqrt{2(9.80)(0.725)(sin45 - 0.120cos45)}

v = 2.97 m/s

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Magnetic fields exist
Effectus [21]

Answer:

Magnetic fields exist near a magnet, farther away from a magnet, and within a magnet.

So, the answer is D. All of the above.

Let me know if this helps!

6 0
3 years ago
A satellite, orbiting the earth at the equator at an altitude of 400 km, has an antenna that can be modeled as a 1.76-m-long rod
ivann1987 [24]

Answer:

The inducerd emf is 1.08 V

Solution:

As per the question:

Altitude of the satellite, H = 400 km

Length of the antenna, l = 1.76 m

Magnetic field, B = 8.0\times 10^{- 5}\ T

Now,

When a conducting rod moves in a uniform magnetic field linearly with velocity, v, then the potential difference due to its motion is given by:

e = - l(vec{v}\times \vec{B})

Here, velocity v is perpendicular to the rod

Thus

e = lvB           (1)

For the orbital velocity of the satellite at an altitude, H:

v = \sqrt{\frac{Gm_{E}}{R_{E}} + H}

where

G = Gravitational constant

m_{e} = 5.972\times 10^{24}\ kg = mass of earth

R_{E} = 6371\ km = radius of earth

v = \sqrt{\frac{6.67\times 10^{- 11}\times 5.972\times 10^{24}}{6371\times 1000 + 400\times 1000} = 7670.018\ m/s

Using this value value in eqn (1):

e = 1.76\times 7670.018\times 8.0\times 10^{- 5} = 1.08\ V

5 0
3 years ago
In the final situation below, the 8.0 kg box has been launched with a speed of 10.0 m/s across a frictionless surface. Find the
Murljashka [212]

Answer:

the energy of the spring at the start is 400 J.

Explanation:

Given;

mass of the box, m = 8.0 kg

final speed of the box, v = 10 m/s

Apply the principle of conservation of energy to determine the energy of the spring at the start;

Final Kinetic energy of the box = initial elastic potential energy of the spring

K.E = Ux

¹/₂mv² = Ux

¹/₂ x 8 x 10² = Ux

400 J = Ux

Therefore, the energy of the spring at the start is 400 J.

8 0
3 years ago
Calculate the pressure exerted on the floor when an elephant who weighs 6000 N stands on one foot which has an area of 20 m2
kondor19780726 [428]

Answer:

300 Pascal

Explanation:

Given

weight or force (F) = 6000 N

area (A) = 20 m²

pressure (p) = ?

we know

the force acting normally per unit area is pressure. So

P = F / A

= 6000 / 20

= 300 Pascal

Hope it will help :)

3 0
3 years ago
Which of the following is a force acting at a distance
wariber [46]
D. gravitational force. is your answer hope this helps
8 0
3 years ago
Read 2 more answers
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