Answer:
the crown is false densty= 12556kg/m^3[/tex]
Explanation:
Hello! The first step to solve this problem is to find the mass of the crown, this is found using the weight of the crown in the air by means of the equation for the weight.
W=mg
W=weight(N)=31.4N
M=Mass
g=gravity=9.81m/S^2
solving for M
m=W/g
The second step is find the volume of crown remembering that when an object is weighed in the water the result is the subtraction between the weight of the object and the buoyant force of the water which is the product of the volume of the crown by gravity by density of water
Where
F=weight in water=28.9N
m=mass of crown=3.2kg
g=gravity=9.81m/S^2
α=density of water=1000kg/m^3
V= crown´s volume
solving for V
finally, we remember that the density is equal to the index between mass and volume
To determine the density of the crown without using the weight in the water and with a bucket we can use the following steps.
1.weigh the crown in the air and find the mass
2. put water in a cylindrical bucket and measure its height with a ruler.
3. Put the crown in the bucket and measure the new water level with a ruler.
4. Subtract the heights, and find the volume of a cylinder knowing the difference in heights and the diameter of the bucket, in order to determine the volume of the crown.
5. find density by dividing mass by volume
Answer:
The answer is "
".
Explanation:
The crucial stress essential for activating the spreading of the crack is 
, the hardness of the strain break is K, as well as the area long of a break is a, for dimensionless Y. Its equation of the length of its surface of the fracture is 50.1 MPa 
on K, 200MPa on , and 1 on Y.
Answer:
resolved shear stress = 22.0 MPa
so we can say that here single crystal will yield because critical resolved shear stress i.e 20.7 MPa is less than resolved shear stress i.e 22.0 MPa
Explanation:
given data
angles φ = 43.1 degrees
angles λ = 47.9 degrees
shear stress = 20.7 MPa (3000 psi)
stress σ = 45 MPa (6500 psi)
solution
we have given shear stress so first we calculate here resolved shear stress that is express as
resolved shear stress = σ cosφ cosλ .................1
here σ is stress and φ and λ are angles given
so put here value we get
resolved shear stress = σ cosφ cosλ
resolved shear stress = 45 cos(43.1) cos(47.9)
resolved shear stress = 22.0 MPa
so we can say that here single crystal will yield because critical resolved shear stress i.e 20.7 MPa is less than resolved shear stress i.e 22.0 MPa
Answer:
C. they need on the job experience I think
This question is incomplete, the complete question is;
Calculate the value of ni for gallium arsenide (GaAs) at T = 300 K.
The constant B = 3.56×10¹⁴ (cm⁻³ K^-3/2) and the bandgap voltage E = 1.42eV.
Answer: the value of ni for gallium arsenide (GaAs) is 2.1837 × 10⁶ cm⁻³
Explanation:
Given that;
T = 300k
B = 3.56×10¹⁴ (cm⁻³ K^-3/2)
Eg = 1.42 eV
we know that, the value of Boltzmann constant k = 8.617×10⁻⁵ eV/K
so to find the ni for gallium arsenide;
ni = B×T^(3/2) e^ ( -Eg/2kT)
we substitute
ni = (3.56×10¹⁴)(300^3/2) e^ ( -1.42 / (2× 8.617×10⁻⁵ 300))
ni = (3.56×10¹⁴)(5196.1524)e^-27.4651
ni = (3.56×10¹⁴)(5196.1524)(1.1805×10⁻¹²)
ni = 2.1837 × 10⁶ cm⁻³
Therefore the value of ni for gallium arsenide (GaAs) is 2.1837 × 10⁶ cm⁻³
