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3 years ago

12

Complete this sentence. Average speed is worked out from dividing _ by

2 answers:

mestny [16]3 years ago

4 0

Average speed is worked out from dividing the total distance by the total time.

Dmitry [639]3 years ago

3 0

Average speed is worked out from dividing distance by time.

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A student sees a newspaper ad for an apartment that has 1330 square feet (ft^2) or floor space. How many square meters of area a

Natasha2012 [34]

<span>=1330 ft^2 x (1m^2/3.25 ft^2)
=124 m^2

</span>

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3 years ago

A 1300 kg steel beam is supported by two ropes. (Figure

Dmitriy789 [7]

Relative to the positive horizontal axis, rope 1 makes an angle of 90 + 20 = 110 degrees, while rope 2 makes an angle of 90 - 30 = 60 degrees.

By Newton's second law,

the net horizontal force acting on the beam is

$R_1 \cos(110^\circ) + R_2 \cos(60^\circ) = 0$

where $R_1,R_2$ are the magnitudes of the tensions in ropes 1 and 2, respectively;

the net vertical force acting on the beam is

$R_1 \sin(110^\circ) + R_2 \sin(60^\circ) - mg = 0$

where $m=1300\,\rm kg$ and $g=9.8\frac{\rm m}{\mathrm s^2}$ .

Eliminating $R_2$ , we have

$\sin(60^\circ) \bigg(R_1 \cos(110^\circ) + R_2 \cos(60^\circ)\bigg) - \cos(60^\circ) \bigg(R_1 \sin(110^\circ) + R_2 \sin(60^\circ)\bigg) = 0\sin(60^\circ) - mg\cos(60^\circ)$

$R_1 \bigg(\sin(60^\circ) \cos(110^\circ) - \cos(60^\circ) \sin(110^\circ)\bigg) = -\dfrac{mg}2$

$R_1 \sin(60^\circ - 110^\circ) = -\dfrac{mg}2$

$-R_1 \sin(50^\circ) = -\dfrac{mg}2$

$R_1 = \dfrac{mg}{2\sin(50^\circ)} \approx \boxed{8300\,\rm N}$

Solve for $R_2$ .

$\dfrac{mg\cos(110^\circ)}{2\sin(50^\circ)} + R_2 \cos(60^\circ) = 0$

$\dfrac{R_2}2 = -mg\cot(110^\circ)$

$R_2 = -2mg\cot(110^\circ) \approx \boxed{9300\,\rm N}$

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2 years ago

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Answer:

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3 years ago

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Answer:

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3 years ago

The magnitude R, measured on the Richter scale, of an earthquake of intensity I is defined as Requalslog StartFraction Upper I

lapo4ka [179]

Answer:

R = 6.8

Explanation:

Given data:

Richter scale $R = log(\frac{I}{I_o})$

where R - magnitude of earthquake of Richter scale

I - quake's intensity $= 10^{6.8} \times I_o$

$I_o$ - minimum intensity earthquake

Plugging all information in the equation to get Richter's scale

$R = log(\frac{10^{6.8} \times I_o}{I_o})$

$R = log(10^{6.8})$

R = 6.8

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3 years ago