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k0ka [10]
3 years ago
14

What is the effect of constant stirring on the solubility of solids and liquids?

Chemistry
1 answer:
vfiekz [6]3 years ago
3 0

Stirring affects how quickly a solute dissolves in a solvent, but has no effect on how much solute will dissolve. The amount of solute that will dissolve is affected by temperature - more will dissolve at higher temperatures. This is called the solubility of the solute

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Answer: This topic circles organizational design: structure, culture, and control.

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6 0
3 years ago
The hydroxide ion concentration of a saturated solution of ca(oh)2 is m. what is the solubility product constant for ca(oh)2
dalvyx [7]
Solubility product constants are values to describe the saturation of ionic compounds with low solubility. A saturated solution is when there is a dynamic equilibrium between the solute dissolved, the dissociated ions, the undissolved and the compound. It is calculated from the product of the ion concentration in the solution. For the base, Ca(OH)2, the dissociation would  be as follows:<span>

Ca(OH)2 = Ca2+ + 2OH-

So, the expression for the solubility product constant would be as follows:

Ksp = [Ca2+] [OH-]^2

let x be the concentration of the Ca2+. So,

</span>
Ksp = [x] [2x]^2
<span>Ksp = 4x^3

You have to substitute the value of the concentration of the calcium hydroxide in the final expression which is not given in the problem statement in order to evaluate Ksp.
</span><span>
</span>
6 0
3 years ago
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