He should confront her about it and if after that point she continues report it to the chess team
I hope that helps you!!!!!!
Answer:
a rock of 50kg should be placed =drock=0.5m from the pivot point of see saw
Explanation:
τchild=τrock
Use the equation for torque in this equation.
(F)child(d)child)=(F)rock(d)rock)
The force of each object will be equal to the force of gravity.
(m)childg(d)child)=(m)rockg(d)rock)
Gravity can be canceled from each side of the equation. for simplicity.
(m)child(d)child)=(m)rock(d)rock)
Now we can use the mass of the rock and the mass of the child. The total length of the seesaw is two meters, and the child sits at one end. The child's distance from the center of the seesaw will be one meter.
(25kg)(1m)=(50kg)drock
Solve for the distance between the rock and the center of the seesaw.
drock=25kg⋅m50kg
drock=0.5m
The force the box is exerting on Manuel is the weight of the box, downward:

and this force is perfectly balanced by the constraint reaction applied by Manuel's hand, pushing upward.
The mass of the ball is 6.67 kg
Explanation:
The momentum of an object is given by:

where
p is the momentum
m is the mass of the object
v is its velocity
It must be noted that momentum is a vector quantity, so it has both magnitude and direction (but here only the magnitude is given).
For the ball in this problem, we have:
v = 1.5 m/s is its velocity
p = 10.0 kg m/s is its momentum
Solving the formula for m, we find the mass of the ball:

Learn more about momentum:
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