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kipiarov [429]
3 years ago
12

11) How many grams of NH, can you make if you use 23 moles of nitrogen gas?

Chemistry
1 answer:
natita [175]3 years ago
5 0

782g

Explanation:

Given parameters:

Number of moles of N₂ = 23moles

Unknown:

Mass of NH₃ = ?

Solution:

We first obtain the balanced chemical equation for this reaction;

    N₂   +    3H₂   →   2NH₃

From the equation we see that;

     1 mole of N₂ produced 2 moles of ammonia

    23 mole of N₂ will yield 2 x 23 = 46moles of ammonia

Now ;

mass of ammonia = number of moles x molar mass

Molar mass of NH₃ = 14 + 3(1) = 17g/mol

 Mass of ammonia = 46 x 17 = 782g

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

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<br> Determine the frequency of a green laser with a wavelength of 532nm.
const2013 [10]

Answer:

5.64*10^{14}m

Explanation:

C = Fλ

C: Speed of light = 3*10^8m/s

f: Frequency (Hz)

λ: Wavelength (m)

Rearrange formula for wavelength:

C/F = λ

\frac{3*10^8}{532*10^{-9}} =5.64*10^{14}m

6 0
3 years ago
3. Two people are playing tug of war. One person pulls to the right with 32 N of force. The other person pulls to the left with
SVETLANKA909090 [29]

The net force = -5 N

The direction : to the left(negative sign)

<h3>Further explanation </h3>

Net force : the sum of all forces acting on an object

Force is a vector quantity that has both magnitude and direction,

We agree that the move up and to the right is a positive sign, while down and to the left is a negative sign.

The direction of the force (horizontal motion) is to the right (+32 N), and to the left (-37 N), so the net force :

\tt \sum F=F~right-F~left\\\\\sum F=32-37\\\\\sum F=-5~N

5 0
2 years ago
Which statement describes vascular plants?
alexandr1967 [171]

Answer:

A vascular plant is any one of a number of plants with specialized vascular tissue. The two types of vascular tissue, xylem and phloem, are responsible for moving water, minerals, and the products of photosynthesis throughout the plant.

Explanation:

7 0
3 years ago
You add 100.0 g of water at 52.0 °C to 100.0 g of ice at 0.00 °C. Some of the ice melts and cools the water to 0.00 °C. When the
lara31 [8.8K]

Answer:

m_{ice} = 65.336\,g

Explanation:

Accoding to the First Law of Thermodynamics, the heat released by the water melts a portion of ice. That is to say:

Q_{water} = Q_{ice}

(100\,g)\cdot \left(4.184\,\frac{J}{kg\cdot ^{\textdegree}C}\right)\cdot (52\,^{\textdegree}C - 0\,^{\textdegree}C) = m_{ice}\cdot \left(333\,\frac{J}{g} \right)

The amount of ice that is melt is:

m_{ice} = 65.336\,g

5 0
3 years ago
In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide dissolved in molten cryolit
natka813 [3]

The given question incomplete, the complete question is:

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,03) dissolved in molten cryolite (Na, Alts).re in the reduction of the Al, o, to pure aluminum. Suppose a current of 1800. A is passed through a Hall-Heroult cell for 37.0 seconds. Calculate the mass of pure aluminum produced Be sure your answer has a unit symbol and the correct number of significant digits.

Answer:

The correct answer is 6.2114 grams.

Explanation:

Based on the given question, the value of current or I have given is 1800 amperes, the time given is 37 seconds, and there is a need to find the mass of the pure aluminum generated in the process. Mass or weight can be determined by using Faraday's first law equation, that is, w = MIt/nF.  

Here, M is the atomic mass, w is the weight of the substance deposited, t is time, I is current, n is the number of moles of the electron, and F is the Faraday's constant, which is 96500 C. In the process mentioned in the question, aluminum oxide is reduced to give rise to pure aluminum, and in the process 3 electrons are gained. So, the value of n will be 3. The M or the atomic mass of Al is 27 gm per mole. Now putting the values in the equation we get,  

w = 27*1800*37 / 3*96500

w = 1798200 / 289500

w = 6.2114 grams

Hence, pure aluminum produced in the process is 6.2114 grams.  

7 0
3 years ago
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