Answer:
In the grapher: The stops are marked with a flat line, velocity with a diagonal line, and acceleration with a curve.
Average speed= Total distance/Total time
Explanation:
Answer:
B. 34.78 m/s
Explanation:
Momentum of a body or an object is given as the product of its velocity and its mass.
Therefore;
Momentum= velocity x mass
But; velocity = ? mass =115 kg , momentum = 4,000 kgm/s
Thus; velocity= momentum/mass
= 4,000/115
= 34.78 m/s
Answer:
Total displacement = 0
Explanation:
He lives his front porch and still returns to his front porch.
Now, displacement is a vector quantity and as such, it is the distance between the initial point of movement and the final point of movement.
In this case the initial point is the same as the final point and thus the displacement is zero.
Answer:
d) 2Fr
Explanation:
We know that the work done in moving the charge from the right side to the left side in the k shell is W = ∫Fdr from r = +r to -r. F = force of attraction between nucleus and electron on k shell. F = qq'/4πε₀r² where q =charge on electron in k shell -e and q' = charge on nucleus = +e. So, F = -e × +e/4πε₀r² = -e²/4πε₀r².
We now evaluate the integral from r = +r to -r
W = ∫Fdr
= ∫(-e²/4πε₀r²)dr
= -∫e²dr/4πε₀r²
= -e²/4πε₀∫dr/r²
= -e²/4πε₀ × -[1/r] from r = +r to -r
W = e²/4πε₀[1/-r - 1/+r] = e²/4πε₀[-2/r} = -2e²/4πε₀r.
Since F = -e²/4πε₀r², Fr = = -e²/4πε₀r² × r = = -e²/4πε₀r and 2Fr = -2e²/4πε₀r.
So W = -2e²/4πε₀r = 2Fr.
So, the amount of work done to bring an electron (q = −e) from right side of hydrogen nucleus to left side in the k shell is W = 2Fr