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3 years ago

During complete combustion, natural gas combines with oxygen to produce _____.

2 answers:

6 0

The carbon dioxide and water are formed, for example:

CH₄ + 2O₂ = CO₂ + 2H₂O
methane

2C₂H₆ + 7O₂ = 4CO₂ + 6H₂O
ethane

C₃H₈ + 5O₂ = 3CO₂ + 4H₂O
propane

Goshia [24]3 years ago

5 0

Natural gas or hydrocarbons combine with oxygen to produce carbon dioxide and water.

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Identify the type of energy involved in each step:

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Radiant energy or electrical energy

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3 years ago

A plate of the steel hull of a ship develops a large crack when the ship strikes a reef. Analysis of the steel’s composition sho

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2 years ago

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Copper(ii) chloride reacts with sodium nitrate to produce copper(ii) nitrate and sodium chloride.

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Answer:

CuCl2 + 2NaNO3 - > Cu(NO3)2 + 2NaCl

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2 years ago

The common pathway for the oxidation of glucose and fatty acids is ________.

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The citric acid cycle should be the answer.

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3 years ago

If you have a 150-gram sample of CrO3: • How many moles of CrO3 do you have? • How many oxygen atoms do you have? • How many gra

docker41 [41]

Answer :

(a) The moles of $CrO_3$ is, 1.5 moles.

(b) The number of oxygen atoms are, $27.099\times 10^{23}$

(c) The mass of oxygen is, 72 grams.

Explanation : Given,

Mass of $CrO_3$ = 150 g

Molar mass of $CrO_3$ = 100 g/mole

Molar mass of oxygen = 16 g/mole

(a) First we have to calculate the moles of $CrO_3$ .

$\text{Moles of }CrO_3=\frac{\text{Mass of }CrO_3}{\text{Molar mass of }CrO_3}=\frac{150g}{100g/mole}=1.5moles$

The moles of $CrO_3$ is, 1.5 moles.

(b) Now we have to calculate the number of oxygen atoms.

In $CrO_3$ , there are 1 atom of chromium and 3 atoms of oxygen.

According to the mole concept,

1 mole of $CrO_3$ contains $3\times 6.022\times 10^{23}$ number of oxygen atoms.

So, 1.5 mole of $CrO_3$ contains $1.5\times 3\times 6.022\times 10^{23}=27.099\times 10^{23}$ number of oxygen atoms.

The number of oxygen atoms are, $27.099\times 10^{23}$

(c) Now we have to calculate the mass of oxygen.

As, 1 mole of $CrO_3$ contains 3 moles of oxygen

So, 1.5 mole of $CrO_3$ contains $1.5\times 3=4.5$ moles of oxygen

$\text{Mass of oxygen}=\text{Moles of oxygen}\times \text{Molar mass of oxygen}$

$\text{Mass of oxygen}=(4.5mole)\times (16g/mole)=72g$

The mass of oxygen is, 72 grams.

3 0

3 years ago