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3 years ago

How many millimeters of 5 M NaCl are required to prepare 1500 mL of 0.002 M NaCl?

Chemistry

1 answer:

timurjin [86]3 years ago

3 0

Answer:

The correct answer is 0.6 mL.

Explanation:

We use the mathematical expression:

Ci x Vi = Cf x Vf

Where Ci is the initial concentration (5 M); Cf and Vf refers to final concentration (0.002 M) and final volume (1500 mL). With the given data, we calculate the initial volume (Vi):

Vi = (Cf x Vf)/Ci = (0.002 M x 1500 mL)/(5 M) = 0.6 mL

Therefore, we need 0.6 mL of 5 M NaCl to prepare the solution with the requested dilution.

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Answer:

Explanation:

That's why rubbing your hands together makes them warmer. ... Friction causes the molecules on rubbing surfaces to move faster, so they have more energy. This gives them a higher temperature, and they feel warmer. Heat from friction can be useful.

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3 years ago

What is clch2ch2ch2oh when oxidized?

Maksim231197 [3]

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What is nucular decay

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3 years ago

The concentration of protein in a urine sample is calculated to be 2.77 μg/mL. What is the concentration of this solution in uni

maxonik [38]

Answer:

The concentration of this solution in units of pounds per gallon is $2.776*10^{-5} \frac{lb}{gal}$

Explanation:

Units of measurement are established models for measuring different quantities. The conversion of units is the transformation of a quantity, expressed in a certain unit of measure, into an equivalent one, which may or may not be of the same system of units.

In this case, the conversion of units is carried out knowing that 1 μg are equal to 2.205*10⁻⁹ Lb and 1 mL equals 0.00022 Gallons. So

$2.77 \frac{ug}{mL} = \frac{2.77 ug}{mL}$

If 1 μg equals 2.205*10⁻⁹ lb, 2.77 μg how many lb equals?

$lb=\frac{2.77ug*2.205*10^{-9}lb }{1ug}$

lb=6.10785*10⁻⁹

So, 2.77 μg= 6.10785*10⁻⁹ lb

Then:

$2.77 \frac{ug}{mL} = \frac{2.77 ug}{mL}=\frac{6.10785*10^{-9}lb }{mL} =\frac{6.10785*10^{-9}lb }{0.00022 gal} =\frac{6.10785*10^{-9}lb }{0.00022 gal}$

You get:

$2.77 \frac{ug}{mL} = 2.776*10^{-5} \frac{lb}{gal}$

<u><em>The concentration of this solution in units of pounds per gallon is </em></u> $2.776*10^{-5} \frac{lb}{gal}$ <u><em></em></u>

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3 years ago

Convert 90.23 kPa into atm

svlad2 [7]

Answer:

The answer is

Explanation:

To convert from kPa to atm we use the conversion

101.325 kPa = 1 atm

Then

90.23 kPa will be

$\frac{90.23}{101.325} \\ =0.89050086...$

We have the final answer as

Hope this helps you

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3 years ago