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Nadusha1986 [10]
3 years ago
14

Describe the results of the experiment that proved atoms contain positive,negative, and neutral particles

Chemistry
1 answer:
Bezzdna [24]3 years ago
5 0

Explanation:

J.J. Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons. ... Rutherford's gold foil experiment showed that the atom is mostly empty space with a tiny, dense, positively-charged nucleus.

there u go :>

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If gas is initially at 350L and 500k then changes to 295K what is the new volume
Dimas [21]
<h2>Hello!</h2>

The answer is:

The new volume is equal to 206.5 L.

<h2>Why?</h2>

To solve this problem, we need to assume that the pressure is constant, and use the Charle's Law equation, so, solving we have:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

We are given:

V_1=350L\\T_1=500K\\T_2=295K

Then, using the Charle's Law equation, we have:

\frac{350L}{500K}=\frac{V_2}{295K}

\frac{350L}{500K}=\frac{V_2}{295K}\\\\V_2=\frac{350L}{500K}*295K=206.5L

Hence, we have that the new volume is equal to 206.5 L.

Have a nice day!

5 0
2 years ago
Be sure to answer all parts.The equilibrium constant, Kc, for the formation of nitrosyl chloride from nitric oxide and chlorine,
djverab [1.8K]

<u>Answer:</u> The reaction proceeds in the forward direction

<u>Explanation:</u>

For the given chemical equation:

2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)

Relation of K_p\text{ with }K_c is given by the formula:

K_p=K_c(RT)^{\Delta n_g}

where,

K_p = equilibrium constant in terms of partial pressure = ?

K_c = equilibrium constant in terms of concentration = 6.5\times 10^4

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature = 35^oC=[35+273]K=308K

\Delta n_g = change in number of moles of gas particles = n_{products}-n_{reactants}=2-3=-1

Putting values in above equation, we get:

K_p=6.5\times 10^4\times (0.0821\times 500)^{-1}\\\\K_p=1583.43

K_p is the constant of a certain reaction at equilibrium while Q_p is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

The expression of Q_p for above equation follows:

Q_p=\frac{(p_{NOCl})^2}{p_{Cl_2}\times (p_{NO})^2}

We are given:

p_{NOCl}=1.76atm

p_{NO}=1.01atm

p_{Cl_2}=0.42atm

Putting values in above equation, we get:

Q_p=\frac{(1.76)^2}{0.42\times (1.01)^2}=7.23

We are given:

K_p=1583.43

There are 3 conditions:

  • When K_{p}>Q_p; the reaction is product favored.
  • When K_{p}; the reaction is reactant favored.
  • When K_{p}=Q_p; the reaction is in equilibrium

As, K_p>Q_p, the reaction will be favoring product side.

Hence, the reaction proceeds in the forward direction

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I think it’s c bc it makes more sense
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The order of the answers are as follows:
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