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3 years ago

14

A ball is released from a hot air balloon moving downward with a velocity of -10.0 meters/second and a height of 1,000 meters. H

ow long did it take the ball to reach the surface of Earth? Given: g = -9.8 meters/second2

2 answers:

Andrews [41]3 years ago

5 0

Your answer should be 14.2

galben [10]3 years ago

4 0

Your answer would be 14.2 Seconds. Welcome

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3 years ago

A. A PH202 student lives next to a construction site and sees a crane with a wrecking ball demolish the building next door. The

netineya [11]

Answer:

The length of cable is 12.5 m

Explanation:

Since, the wrecking ball completes 1 oscillation, in the same time, as it takes for the rock to complete 5 oscillations.

Therefore,

Time Period of Wrecking Ball = 5 (Time Period of Rock)

Since,

Time Period of Pendulum = 2π√(L/g)

Therefore,

2π√(L₁/g) = 5[2π√(L₂/g)]

√L₁ = 5√L₂

Squaring on both sides:

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Therefore,

L₁ = 25 (0.5 m)

<u>L₁ = 12.5 m</u>

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3 years ago

Your friend, Tim, is playing with his sled. He ties a rope to his sled and attaches it to Lar's snowmobile. Tim has a mass of 71

kykrilka [37]

The maximum speed of Tim is 16.95 m/s.

The given parameters:

Mass of the rope, m = 71 kg
Tension on the rope, T = 220 N
Coefficient of kinetic friction, = 0.1
Time of motion, t = 8 s

<h3>What is Newton's second law of motion?</h3>

Newton's second law of motion states that, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

The net force on Tim is calculated by applying Newton's second law of motion as follows;

$T - \mu _k F_n = ma\\\\T - \mu _k F_n = m\frac{v}{t} \\\\T - \mu_k mg = m\frac{v}{t} \\\\t(\frac{T - \mu_k mg}{m} )= v\\\\8 (\frac{220 \ -\ 0.1 \times 71 \times 9.8}{71} ) =v \\\\ 16.95 \ m/s = v$

Thus, the maximum speed of Tim is 16.95 m/s.

Learn more about net horizontal force here: brainly.com/question/21684583

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