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tatyana61 [14]
3 years ago
15

This chart shows the experimental design of four students who are all observing what kind of bird seed birds tend to eat more of

ten.
Student 1
- Performed the experiment once
- Used the same area, same time of day, and same amount of seeds
Student 2
- Repeated the experiment 5 times
- Used the same area, different time of day, and different amount of seeds
Student 3
- Repeated the experiment 2 times
- Used the same area, different time of day, and different amount of seeds
Student 4
- Repeated the experiment 5 times
- Used the same area, same time of day, and same amount of seeds

Which student is the most likely to have reproducible results?

Student 1
Student 2
Student 3
Student 4
Chemistry
2 answers:
densk [106]3 years ago
7 0

Answer:

Student 2

Explanation:

Student 2 repeated the experiment with different seeds at different times 5 different times, ensuring he/she got the most reliable answers.

ki77a [65]3 years ago
4 0

Answer:Student 2

Explanation:

Student 2 repeated the experiment several times with different seeds to make sure the experiment would come out with the same answers and was reliable, using the same area would make sure the environment wouldn't interfere. The other students didn't do all the things that student 2 needed for the experiment.

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Which types of electron orbitals will have higher energy than a 4d orbital?
alexdok [17]

Answer:

D) 4f

Explanation:

To determine which electron orbital that will have higher energy than a 4d orbital, we write the electron configuration starting with s-orbital.

1s

2s         2p

3s         3p          3d       3f

4s         4p          4d       4f

5s         5p           5d       5f

6s         6p          6d       6f

7s         7p           7d       7f

In ascending order, 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 3f, <u>4d</u><em>,</em> 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, 6f, 7d, 7f.

From the electronic configuration formula above, the electron orbitals that have higher energy than a 4d orbital are 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, 6f, 7d, 7f.

Therefore, 4f is the correct answer.

8 0
3 years ago
Which of the following describes the process of deflation?
goldenfox [79]
The answer is C. <span>The wind removes surface particles, resulting in lower land surface.

Deflation is the process of lifting and moving of tiny particles of soil or sand, brought about by the wind. It can also be associated with soil erosion. This is a common phenomenon in deserts and sand dune areas near the coast.</span>
4 0
3 years ago
Calculate the amount of energy required to melt 500 g of ice at 0oc. (δhfus=5.96 kj/mole; δhfus is the energy required to melt i
marta [7]
When you want to melt an ice, you only need the latent energy of fusion, <span>δhfus. We use the given value, then multiply this with the given amount to determine the amount of energy. Since the energy is per mole basis, use the molar mass of ice which is 18 g/mol. The solution is as follows:

</span>ΔH = 5.96 kJ/mol * 1 mol/18 g * 500 g
<em>ΔH = 165.56 kJ</em><span>
</span>
3 0
3 years ago
2NOCl(g) ↔ 2NO(g) + Cl2(g) with K = 1.6 x10–5. In an experiment, 1.00 mole of pure NOCl and 1.00 mole of pure Cl2 are placed in
poizon [28]

Answer: 3.8\times 10^{-3}M

Explanation:

Moles of  NOCl = 1 mole

Moles of  Cl_2 = 1 mole

Volume of solution = 1 L

Initial concentration of NOCl = 1 M

Initial concentration of Cl_2 = 1 M

The given balanced equilibrium reaction is,

                  2NOCl(g)\rightleftharpoons 2NO(g)+Cl_2(g)

Initial conc.          1 M                      0M          1 M

At eqm. conc.     (1-2x) M              (2x) M       (1+x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[NO]^2[Cl_2]}{[NOCl]^2}

The K_c= 1.6\times 10^{-5}}

Now put all the given values in this expression, we get :

{1.6\times 10^{-5}}=\frac{(2x)^2\times (1+x)}{(1-2x)^2}

By solving the term 'x', we get :

x=0.0019

Concentration of NO at equilibrium= (2x) M  =  2\times 0.0019=3.8\times 10^{-3}M

6 0
3 years ago
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