Answer:
4 NH3 (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (l)
This is an oxidation-reduction (redox) reaction:
4 N-III - 20 e- → 4 NII
(oxidation)
10 O0 + 20 e- → 10 O-II
(reduction)
NH3 is a reducing agent, O2 is an oxidizing agent.
Explanation:
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Methane.
Water - H2O
Methane - CH4
Methane has 2 more hydrogens than water.
A feature that an iron metal has is a sea of electrons
