Number 1 is Rio Grande and number 2 is St. Lawrence River
Step-by-step explanation:
The solution to the equation x(x+4) = 6 is x = -2 + √10 or x = -2 - √10 after solving with the quadratic formula.
<h3>What is a quadratic equation?</h3>
Any equation of the form
where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
As we know, the formula for the roots of the quadratic equation is given by:

We have an equation:
x(x + 4) = 6
By distributive property:
x² + 4x = 6
x² + 4x - 6 = 0
a = 1, b = 4, c = -6
Plugging all the values in the formula:

After calculating:


Thus, the solution to the equation x(x+4) = 6 is x = -2 + √10 or x = -2 - √10 after solving with the quadratic formula.
Learn more about quadratic equations here:
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Option A: z + 1
Option B: 6 + w
Option D: 
Solution:
Let us first define the polynomial.
A polynomial can have constants, variables, exponents and fractional coefficients.
A polynomial cannot have negative exponents, fractional exponents and never divided by a variable.
<u>To find which expressions are polynomial:</u>
Option A: z + 1
By the definition, z + 1 is a polynomial.
It is polynomial.
Option B: 6 + w
By the definition, 6 + w is a polynomial.
It is polynomial.
Option C: ![y^{2}-\sqrt[3]{y}+4](https://tex.z-dn.net/?f=y%5E%7B2%7D-%5Csqrt%5B3%5D%7By%7D%2B4)
![y^{2}-\sqrt[3]{y}+4=y^{2}-{y}^{1/3}+4](https://tex.z-dn.net/?f=y%5E%7B2%7D-%5Csqrt%5B3%5D%7By%7D%2B4%3Dy%5E%7B2%7D-%7By%7D%5E%7B1%2F3%7D%2B4)
Here, y have fractional exponent.
So, it is not a polynomial.
Option D: 
By the definition,
is a polynomial.
It is polynomial.
Hence z + 1, 6 +w and
are polynomials.
Answer- 6.25 Your welcome.