Answer:
The most appropriate structure given the sparse spectral data is<u><em> 4-acetyl benzoic acid (see attached).</em></u>
Explanation:
It is difficult to accurately elucidate the structure of this compound without its chemical formula. But from the 1H NMR spectral data shows a total of 8 hydrogen atoms:
- 12.71 (1H. s) - confirms presence of carboxylic acid proton, C=O-OH
- 8.04 (2H, d) - confirms aromatic hydrogen
- 7.30 (2H, d) - confirms aromatic hydrogen
- 2.41 (3H,s) - confirms C=C hydrogen or ketone O=C-RCH3
The attached files show the structure and the neighboring hydrogen atoms.
<u>The most likely structure i 4-acetyl benzoic acid</u>
When nitrous acid (HNO₂) dissociates in water (H₂O), the reaction that best captures this process is:
HNO₂ (aq.) + H₂O ↔ H₃O⁺ (aq.) + NO₂⁻ (aq.)
How does one know about HNO₂?
- The chemical designation for nitrous acid is HNO₂, and it is a monoprotic acid. Three elements—hydrogen(H), oxygen(O), and nitrogen(N), all compose it.
- It is highly fragile in nature and only occurs in solutions.
- It is employed to convert amines into diazonium salts.
Is HNO₂ a basic or an acid?
Acidity is assigned to nitrous acid (HNO₂). Once dissolved in water, it gives out H+ ions. Acid is a chemical that produces H+ ions in a water-based solution or gives the protons to other molecules.
Thus, HNO₂ is acid because it causes a mixture of water to contain H+ ions. In a 10 mM concentration, it possesses a pH of 2.67.
Learn more about nitrous acid here:
brainly.com/question/17055219
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Answer:
If the hydrated salt is overheated, it causes the anhydrous salt to decompose, causing the product to be lost as gas. The reported percentage of water loss will be too high because the gap between the initial measurement and final (which will be lower due to loss of sample) measurement will widen.
Answer:
Explanation:
mass of the solution m = 1.6 + 75 = 76.6 g
fall in temperature = 25 - 23.34 = 1.66°C
heat absorbed = mass x specific heat x fall in temperature
= 76.6 x 1.66 x 4.18
= 531.5 J .
= .5315 kJ .
mol weight of ammonium nitrate = 80 g
heat absorbed by 1.6 g = .5315 kJ
heat absorbed by 80 g or one mole = 26.575 kJ
enthalpy change ΔH = +26.575 kJ
b )
enthalpy of hydration = 2630 kJ / mol
lattice energy = enthalpy of hydration + enthalpy change
= 2630 + 26.575
= 2656.575 kJ .
