Answer: 9.9 grams
Explanation:
To calculate the moles, we use the equation:
a) moles of 
b) moles of 
According to stoichiometry :
1 mole of combine with 1 mole of
Thus 0.33 mole of will combine with =
mole of
Thus is the limiting reagent as it limits the formation of product.
As 1 mole of give = 1 mole of 
Thus 0.33 moles of give =
of
Mass of 
Thus theoretical yield (g) of produced by the reaction is 9.9 grams
Answer:
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Explanation:
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Covalent bond should be right
Answer:
6.2
Explanation:
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(a) 3.33 mol Bi
Explanation:
Step 1: Convert 283 g to moles
Bi Molar Mass - 208.98 g/mol × 2 = 417.98 g/mol
O Molar Mass - 16.00 g/mol × 3 = 48.00 g/mol
283 g Bi₂O₃ ÷ 465.98 g/mol = 0.0607 mol Bi₂O₃
Step 2: Find the conversion from Bi₂O₃ to Bi
1 mole of Bi₂O₃ equals 2 moles of Bi
Step 3: Use Dimensional Analysis
1.66316 mol · = 3.32632 mol Bi
3.32632 mol Bi ≈ 3.33 mol Bi
What is bismuth oxide used for?
Bismuth oxides have been considered as an interesting material because of their dielectric properties and have been used for applications such as optical coatings, metal-insulator-semiconductor capacitors and microwave-integrated circuits.
What is bismuth used for in everyday life?
Bismuth finds its main uses in pharmaceuticals, atomic fire alarms and sprinkler systems, solders and other alloys and pigments for cosmetics, glass and ceramics. It is also used as a catalyst in rubber production
Learn more about bismuth oxide:
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