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Sloan [31]
3 years ago
9

A bodybis thrown vertically upward with velocity of 30m/s calculate the the maximum height attained​

Physics
2 answers:
givi [52]3 years ago
6 0

Answer:

Answer in the attachment

Gennadij [26K]3 years ago
5 0

Explanation:

  • Initial velocity(v)=30 m/s
  • Final velocity(u)=0 m/s
  • Acceleration due to gravity(g)=9.8m/s²
  • Height(h)=?

Now,

By the third equation of motion, we have

  • v²=u²+2gh
  • 30²=0²+2×9.8×h
  • 900=0+19.6h
  • 900=19.6h
  • 900/19.6=h
  • h=45.918 m
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The tension in the string B) It quadruples.

Explanation:

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T= m\frac{v^2}{r}

where:

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In this problem, we are told that the speed of the ball is doubled, so

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Substituting into the previous equation, we find the new tension in the string:

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3 years ago
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sliding friction.
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3 years ago
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Answer:

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the correct answer is D

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