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Evgen [1.6K]
3 years ago
13

At 1 AM, a handsome astronomy instructor has just completed a late night dinner with Jennifer Garner and observes a nearly full

moon high in the eastern sky. What phase is the moon in and how long will it take before the next full moon occurs?
Physics
1 answer:
oksano4ka [1.4K]3 years ago
6 0

Answer:

The correct answer is: waxing gibbous, 3 days

Explanation:

Waning quarter moon: hair removal time and bangs cuts.

The growing quarter as a moment of growth, development and evolution. On the contrary, the waning moon is associated with a time of completion, debugging or liquidation of pending issues.

We must take advantage of the influence of the lunar cycle in our favor according to the action we are going to take. If you have trouble growing your hair, try to go to the hairdresser in a crescent moon: it will grow faster. It is no nonsense. Since I cut my bangs to the Cleopatra, the touch-ups last me for another 1-1.5 weeks. As I reviewed the bangs in a growing room, in just a couple of weeks I was returning to the hairdresser.

That affects hair removal. There are many people who take appointments to the beautician to shave by consulting the lunar calendar. The hair removal done as soon as the dwindling is the best because it lasts longer, lasts for another week until the next appointment.

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Use the Bohr model to address this question. When a hydrogen atom makes a transition from the 5 th energy level to the 2nd, coun
iris [78.8K]

Answer:

A. 2.82 eV

B. 439nm

C. 59.5 angstroms

Explanation:

A. To calculate the energy of the photon emitted you use the following formula:

E_{n1,n2}=-13.4(\frac{1}{n_2^2}-\frac{1}{n_1^2})     (1)

n1: final state = 5

n2: initial state = 2

Where the energy is electron volts. You replace the values of n1 and n2 in the equation (1):

E_{5,2}=-13.6(\frac{1}{5^2}-\frac{1}{2^2})=2.82eV

B. The energy of the emitted photon is given by the following formula:

E=h\frac{c}{\lambda}   (2)

h: Planck's constant = 6.62*10^{-34} kgm^2/s

c: speed of light = 3*10^8 m/s

λ: wavelength of the photon

You first convert the energy from eV to J:

2.82eV*\frac{1J}{6.242*10^{18}eV}=4.517*10^{-19}J

Next, you use the equation (2) and solve for λ:

\lambda=\frac{hc}{E}=\frac{(6.62*10^{-34} kg m^2/s)(3*10^8m/s)}{4.517*10^{-19}J}=4.39*10^{-7}m=439*10^{-9}m=439nm

C. The radius of the orbit is given by:

r_n=n^2a_o   (3)

where ao is the Bohr's radius = 2.380 Angstroms

You use the equation (3) with n=5:

r_5=5^2(2.380)=59.5

hence, the radius of the atom in its 5-th state is 59.5 anstrongs

8 0
3 years ago
A heavy boy and a lightweight girl are balanced on a mass-less seesaw. If they both move forward so that they are one-half their
Rom4ik [11]

Answer:

b) Nothing will happen,  the sea saw will still be balanced.

Explanation:

b) Nothing will happen,  the sea saw will still be balanced.

Reason:-

When two kids are balanced, the sum of torques on the seesaw will be zero.

if each kid, reduces their distances by half, then the torque of each kid will be half and the sum of torque of each on the seesaw will be zero.

Therefore the seesaw is balanced

4 0
3 years ago
Read 2 more answers
What happens when red, blue, and green light come together?
Alja [10]

Answer:

I believe if red, blue, and green light come together it would produce White light.

8 0
2 years ago
Read 2 more answers
Which term refers to energy derived from heat inside the earth
tino4ka555 [31]
I think the answer is Geothermal energy. 
3 0
3 years ago
Consider a mechanical clutch that consists of two heavy disks that can engage or disengage. At the beginning disk 1 with mass m1
miv72 [106K]

Answer:

w = 4,786 rad / s ,  f = 0.76176 Hz

Explanation:

For this problem let's use the concept of angular momentum

       L = I w

The system is formed by the two discs, during the impact the system remains isolated, we have the forces are internal, this implies that the external torque is zero and the angular momentum is conserved

Initial Before sticking

      L₀ = 0 + I₂ w₂

Final after coupling

      L_{f} = (I₁ + I₂) w

The moments of inertia of a disk with an axis of rotation in its center are

      I = ½ M R²

How the moment is preserved

      L₀ = L_{f}

      I₂ w₂ = (I₁ + I₂) w

      w = w₂ I₂ / (I₁ + I₂)

Let's reduce the units to the SI System

      d₁ = 60 cm = 0.60 m

      d₂ = 40 cm = 0.40 m

      f₂ = 200 min-1 (1 min / 60 s) = 3.33 Hz

Angular velocity and frequency are related.

      w₂ = 2 π f₂

      w₂ = 2π 3.33

      w₂ = 20.94 rad / s

Let's replace

       w = w₂ (½ M₂ R₂²) / (½ M₁ R₁² + ½ M₂ R₂²)

       w = w₂ M₂ R₂² / (M₁ R₁² + M₂ R₂²)

Let's calculate

      w = 20.94 8 0.40² / (12 0.60² + 8 0.40²)

      w = 20.94 1.28 / 5.6

      w = 4,786 rad / s

Angular velocity and frequency are related.

      w = 2π f

      f = w / 2π

      f = 4.786 / 2π

      f = 0.76176 Hz

7 0
3 years ago
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