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Evgen [1.6K]
3 years ago
13

At 1 AM, a handsome astronomy instructor has just completed a late night dinner with Jennifer Garner and observes a nearly full

moon high in the eastern sky. What phase is the moon in and how long will it take before the next full moon occurs?
Physics
1 answer:
oksano4ka [1.4K]3 years ago
6 0

Answer:

The correct answer is: waxing gibbous, 3 days

Explanation:

Waning quarter moon: hair removal time and bangs cuts.

The growing quarter as a moment of growth, development and evolution. On the contrary, the waning moon is associated with a time of completion, debugging or liquidation of pending issues.

We must take advantage of the influence of the lunar cycle in our favor according to the action we are going to take. If you have trouble growing your hair, try to go to the hairdresser in a crescent moon: it will grow faster. It is no nonsense. Since I cut my bangs to the Cleopatra, the touch-ups last me for another 1-1.5 weeks. As I reviewed the bangs in a growing room, in just a couple of weeks I was returning to the hairdresser.

That affects hair removal. There are many people who take appointments to the beautician to shave by consulting the lunar calendar. The hair removal done as soon as the dwindling is the best because it lasts longer, lasts for another week until the next appointment.

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Based on this how many Carbon<br> Atoms would be on the products <br> Side
pashok25 [27]
Please clarify the question, and add more information before I can answer that, I’d need to know the amount of carbon atoms.
8 0
2 years ago
HELP PLSSS I HAVE AN EXAM MONDAY AND I THINK THIS IS GONNA BE ON ITTTT
il63 [147K]
<h2>Answer:</h2>

(a) 3.2 x 10²s

(b) 0.9 m/s (S 13 E)

(c) 2.9 x 10²m

<h2>Explanation:</h2>

The sketch illustrating the scenario has been attached to this response.

As shown;

The fish swims due east with a velocity V_{x} = 0.2m/s

The river current has a velocity V_{y} due South = 0.9m/s

The resultant of the velocity is V

The width of the river is x = 64m

(a) To calculate how long it took the fish to get across the river, we know that velocity is the rate of change in distance, therefore we can use the relation;

V = \frac{d}{t}      -------------(i)

Where;

V = velocity of the fish = V_{x} = 0.2m/s

d = distance from the start to the end = width of the river = x = 64m

t = time taken to move for that distance

Make t subject of the formula in equation (i);

t = \frac{d}{V}

Substitute the values of d and V into the equation;

t = \frac{64m}{0.2m/s}

t = 320 s

t = 3.20 x 10²s

Therefore, the time taken for the fish to get across the river is 3.20 x 10²s

(b) The resulting vector of the fish is V whose magnitude is the algebraic sum of vectors  V_{x} and  V_{y}, and direction is given by θ. i.e

<em>The magnitude of the resulting vector is;</em>

|V| = \sqrt{(V_x)^2 + (V_y)^2}

|V| = \sqrt{(0.2)^2 + (0.9)^2}

|V| = \sqrt{(0.04) + (0.81)}

|V| = \sqrt{(0.85)}

|V| = 0.92m/s

|V| ≅ 0.9m/s

<em>The direction of the resulting vector θ and is given by;</em>

tan θ = \frac{V_y}{V_x}

tan θ = \frac{0.9}{0.2}

tan θ = 4.5

θ = tan⁻¹ ( 4.5)

θ = 77.47° South of East.

θ  ≈ 77.5° South of East.

Subtracting θ = 77.5° from 90° gives its value East of South

i.e

90 - 77.5 = 12.5° East of South

<em>This can also be written as S12.5°E</em>

<em>Approximating to the nearest whole number gives </em>S 13 E

Therefore, the resulting velocity of the fish is 0.9m/s in the direction S13°E

(c) When the fish arrives on the opposite bank, its distance from being at the point directly across from where it started is the product of the velocity of the river current and the time taken by the fish to get across the river. This point is equivalent to k as shown in the diagram.

Therefore;

distance = velocity of river current x time taken

distance = 0.9m/s x 3.20 x 10²s

distance = 2.88 x 10²m

distance ≅ 2.9 x 10²m

<em>Notice that the velocity of the river current is used since that's the velocity of the fish on the y-axis.</em>

<em />

<em />

7 0
2 years ago
You have been training and can run a mile in 6.5 minutes. How long would it take to run a lap around the outside track, which is
Paha777 [63]

Answer:

1 minute 36.85 seconds

Explanation:

First we need to convert the miles into meters, as the demanded result should be in meters.

1 mile = 1,609.34 meters

Also, 6.5 minutes should be converted into seconds.

1 minute = 60 seconds

6.5 x 60 = 390 seconds

Now we need to divide the miles with the seconds to see how much meters have been run in a second.

1,609.34 / 390 = 4.13 meters

The suggested meters now should be divided with the distance run in one second.

400 / 4.13 = 96.85 seconds

So we get a result of 96.85 seconds, or 1 minute 36.85 seconds.

5 0
2 years ago
A bungee cord with a spring constant of 800 StartFraction N over m EndFraction stretches 6 meters at its greatest displacement.
zalisa [80]

Explanation:

EE = ½ kx²

EE = ½ (800 N/m) (6 m)²

EE = 14,400 J

8 0
3 years ago
Explain how you can use the factors of production to produce a fruit juice in a production company
frozen [14]

Answer:

The factors of production include Land, Labour, Capital and Enterpreneurship

Explanation:

The fruit could be apple, orange , pineapple etc which are usually grown on land . They are tended to by people to ensure there is maximum yield. These people provide the required labour needed.

The cost of planting and payment of workers usually comes from the capital which is often used in running the business by the owner which makes certain decisions to ensure the fruit company is in place. All these factors work hand in hand to ensure production of fruit in a production company is possible.

7 0
2 years ago
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