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Alisiya [41]
3 years ago
5

With which part of the brain is awareness typically associated?

Physics
2 answers:
Kitty [74]3 years ago
8 0

Answer:

Cerebral Cortex

Explanation:

The cerebral cortex has a left and a right hemisphere. Each hemisphere can be divided into four lobes: the frontal lobe, temporal lobe, occipital lobe, and parietal lobe. The lobes are functional segments. They specialize in various areas of thought and memory, of planning and decision making, and of speech and sense perception.

weeeeeb [17]3 years ago
4 0

Answer:cerebral cortex

Explanation:

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Two conducting spheres are mounted on insulating rods. They both carry some initial electric charge, and are far from any other
natka813 [3]

The question is incomplete. The complete question is :

Two conducting spheres are mounted on insulating rods. They both carry some initial electric charge, and are far from any other charge. Their charges are measured. Then, the spheres are allowed to briefly touch, and the charge in one of them (sphere A) is measured again. These are the measured values:

 a). Before contact:

Sphere A = 4.8 nC

Sphere B = 0 nC

What is the charge on sphere B after contact, in nC?

b). Before contact:

Sphere A = 2.9 nC

Sphere B = -4.4 nC

What is the charge on sphere B after contact, in nC?

Solution :

It is given that there are two spheres that are conducting and are mounted on an insulating rods which carry a initial charge and they are briefly touched and then one of the charge is measured.

Here the charge becomes divided when  both the spheres are connected and then removed.

a). charge after they are charged

   $Q = \frac{q_1+q_2}{2}$

    $Q = \frac{4.8+0}{2}$

      = 2.4 nC

b). The charge is

    $Q = \frac{q_1-q_2}{2}$

    $Q = \frac{2.9-4.4}{2}$

      = -0.75 nC    

6 0
3 years ago
The temperature of 20 liters of helium gas is increased from 100°K to 300°K. If the pressure was kept constant, the new volume w
slavikrds [6]

Answer:

New volume (V2) = 60 liter

Explanation:

Given:

Amount of helium (V1) = 20 Liter

Temperature (T1) = 100°K

Temperature (T2) = 300°K

Find:

New volume (V2)

Computation:

According to Gas Law:

V1 / T1 = V2 / T2

20 / 100°K = V2 / 300°K

V2 = 60 liter

New volume (V2) = 60 liter

8 0
3 years ago
Un movil aumenta su velocidad de 10m/s a 20m/s acelerando uniformemente a razon de 5m/s2 ¿que distancia logro en dicha operacion
Kruka [31]

v₀ = initial velocity of the mobile = 10 m/s

v = final velocity of the mobile = 20 m/s

a = acceleration of the mobile = 5 m/s²

d = distance traveled during this operation = ?

Using the kinematics equation

v² = v²₀ + 2 a d

inserting the above values in the equation

20² = 10² + 2 (5) d

400 = 100 + 10 d

subtracting 100 both side

400 - 100 = 100 - 100 + 10 d

300 = 10 d

dividing both side by 10

300/10 = 10 d/10

d = 30 m

hence mobile travels 30 m.

8 0
3 years ago
An electron, starting from rest and moving with a constant acceleration, travels 2.0 cm in 5.0 ms. What is the magnitude of this
IrinaK [193]
 <span>s=2.7 centimeters = 0.027 meters 
t=3.9 milliseconds = 0.0039 seconds 

s=(1/2)a*t^2 
so 
a=(2.7*2)/(0.0039)^2 
= 355,029.58 m/s^2 

a=355,029.58 m/s^2 = 355.02958 km / s^2</span>
7 0
2 years ago
A horizontal spring with spring constant 750 N/m is attached to a wall. An athlete presses against the free end of the spring, c
ANTONII [103]

Answer:

37.5 N Hard

Explanation:

Hook's law: The force applied to an elastic material is directly proportional to the extension provided the elastic limit of the material is not exceeded.

Using the expression for hook's law,

F = ke.............. Equation 1

F = Force of the athlete, k = force constant of the spring, e = extension/compression of the spring.

Given: k = 750 N/m, e = 5.0 cm = 0.05 m

Substitute into equation 1

F = 750(0.05)

F = 37.5 N

Hence the athlete is pushing 37.5 N hard

4 0
3 years ago
Read 2 more answers
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