Molar mass CO₂ = 12 + 16 x 2 = 44.0 g/mol
1 mole ------------ 44.0 g
9 moles --------- ? ( mass CO₂)
mass CO₂ = 9 x 44.0 / 1
mass CO₂ = 396 / 1
= 396 g of CO₂
hope this helps!
Answer:
19 years
Explanation:
Tritium follows a first-order decay which can be represented by the following expression.
![ln(\frac{[H]_{t}}{[H]_{0}} )=-k.t](https://tex.z-dn.net/?f=ln%28%5Cfrac%7B%5BH%5D_%7Bt%7D%7D%7B%5BH%5D_%7B0%7D%7D%20%29%3D-k.t)
where,
[H]t is the concentration of tritium at a certain time t
[H]₀ is the initial concentration of tritium
k is the rate constant
If we know the half-life (t1/2), we can calculate the rate constant.
![k=\frac{ln2}{t_{1/2}} =\frac{ln2}{12.3y} =0.0564y^{-1}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7Bln2%7D%7Bt_%7B1%2F2%7D%7D%20%3D%5Cfrac%7Bln2%7D%7B12.3y%7D%20%3D0.0564y%5E%7B-1%7D)
![ln(\frac{[H]_{t}}{[H]_{0}} )=-k.t\\ln(\frac{0.34[H]_{0}}{[H]_{0}} )=-(0.0564y^{-1}).t\\t=19y](https://tex.z-dn.net/?f=ln%28%5Cfrac%7B%5BH%5D_%7Bt%7D%7D%7B%5BH%5D_%7B0%7D%7D%20%29%3D-k.t%5C%5Cln%28%5Cfrac%7B0.34%5BH%5D_%7B0%7D%7D%7B%5BH%5D_%7B0%7D%7D%20%29%3D-%280.0564y%5E%7B-1%7D%29.t%5C%5Ct%3D19y)
Answer:
Option a, centimeter
Explanation:
Foot, Inch and Yard are units used in America, UK, and other english-speaking countries.
These countries are currently reviewing the possibility of adapting the measures to the SI. The centimeter is a unit derived from the meter, base unit for measuring length in the SI, and corresponds to the cgs system, where in addition to the centimeter, is constituted by gram and second units
The ozone layer absorbs radiation from the sun, helping to increase the temperature in the upper portion of the stratoshpere
Answer: The answer is True
Explanation: I hope my answer helps :)