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katen-ka-za [31]
3 years ago
15

A 40.0-kg solid cylinder is rolling across a horizontal surface at a speed of 6.0 m/s. how much work is required to stop it

Physics
1 answer:
jeyben [28]3 years ago
3 0
One way of thinking of energy is to say the energy is the ability of the body to do work. If you have a body that is moving that body has kinetic energy, as said above this energy can be used to do work. The amount of work done is equal to the amount of energy that body has.
In our case cylinder has the following kinetic energy:
E_k=m\frac{v^2}{2}\\
E_k=40\frac{6^2}{2}\\
E_k=40\cdot18\\
E_k=720$J
And that is exaclty how much work you would have to put in to stop the cylinder.

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erma4kov [3.2K]

Answer:

h = 269.6 m

Explanation:

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P_{top} = P_{bottom} - \rho g h

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P_{top} = (730\times 10^{-3})(13.6 \times 10^3)(9.81)

P_{top} = 0.974 \times 10^5

now we have

(1.007 - 0.974)\times 10^5 = 1.25 (9.81) h

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3 years ago
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viktelen [127]
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5 0
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Step 7- Communicate. Present/share your results. Replicate.

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If C is 1kg and D is 100kg, and the initial velocities of both balls are 5m/s, how would the magnitude of the forces exerted by
kupik [55]

Answer:

Explanation:

The forces exerted by each mass is best understood in terms of their momentum.

Momentum is a sort of compelling force or impulse. It is given as:

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     Velocity  = 5m/s

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Substance D:

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      Velocity  = 5m/s

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3 years ago
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Answer:

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