Answer:
6.30 L
Explanation:
P1 = P, V1 = 4.20 L, T1 = T
P2 = P/3, V2 = ?, T2 = T/2
Where, V2 be the final volume.
Use ideal gas equation
By substituting the values, we get
V2 = 6.30 L
Increased lamp voltage is achieved by turning the light intensity dial.
To enlarge the diameter of the hole and let more light through the slide, the iris diaphragm was modified.
Condenser: Position it higher and closer to the slide's bottom to better direct light to the centre of the slide.
<h3>
How do you adjust the light level on a microscope?</h3>
Utilize the brightness adjustment knob to change the brightness. Turn the brightness control knob while looking through the eyepieces to make sure there is no glare in the field of view.
Use a daylight balancing filter if your compound microscope has a certain sort of illumination. It typically rests directly on top of the luminator or in a filter holder above the light. This filter is blue.
The daylight balancing filter will correct the colour temperature and produce a higher-quality image if your microscope is lighted by tungsten or halogen (and a better colour image). This blue filter is not necessary if your microscope is an LED.
To learn more about light level on a microscope, visit:
brainly.com/question/14727797
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Answer:
Minimum diameter of the camera lens is 22.4 cm
The focal length of the camera's lens is 300cm
Explanation:
y = Resolve distance = 0.3 m
h = Height of satellite = 100 km
λ = Wavelength = 550 nm
Angular resolution
From Rayleigh criteria
Minimum diameter of the camera lens is 22.4 cm
Relation between resolvable feature, focal length and angular resolution
The focal length of the camera's lens is 300cm
D. The osculations show a variable rate of motion. Hope this helps:)
B4 the tackle:
<span>The linebacker's momentum = 115 x 8.5 = 977.5 kg m/s north </span>
<span>and the halfback's momentum = 89 x 6.7 = 596.3 kg m/s east </span>
<span>After the tackle they move together with a momentum equal to the vector sum of their separate momentums b4 the tackle </span>
<span>The vector triangle is right angled: </span>
<span>magnitude of final momentum = √(977.5² + 596.3²) = 1145.034 kg m/s </span>
<span>so (115 + 89)v(f) = 1145.034 ←←[b/c p = mv] </span>
<span>v(f) = 5.6 m/s (to 2 sig figs) </span>
<span>direction of v(f) is the same as the direction of the final momentum </span>
<span>so direction of v(f) = arctan (596.3 / 977.5) = N 31° E (to 2 sig figs) </span>
<span>so the velocity of the two players after the tackle is 5.6 m/s in the direction N 31° E </span>
<span>btw ... The direction can be given heaps of different ways ... N 31° E is probably the easiest way to express it when using the vector triangle to find it</span>
