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yarga [219]
2 years ago
14

A helium balloon has a pressure of 0.2 kPa and a volume of 15 L. If the pressure increases to 0.5 kPa, what volume will the ball

oon have?
1.5 L

6.0 L

0.007 L

37.5 L
Chemistry
1 answer:
Alex17521 [72]2 years ago
7 0

Answer:

6.0 L

Explanation:

For this question, we can use

P1×V1= P2 × V2

where

P1 (initial pressure)= 0.2 kPa

V1 (initial volume)= 15L

P2 (final pressure)= 0.5 kPa

V2(final volume)= ?

Since we are trying to find final volume, we can rearrange the equation to make V2 the subject.

V2= (P1 × V1)/ P2

V2= (0.2 ×15)/0.5

V2 =6 L

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A. 0.83

Explanation:

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Which accurately completes the statement? Conduction involves the transfer of ___________ due to the movement of particles. Grou
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Explanation:

conduction involves the transfer of molecules due to the movement of particles

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3 years ago
1. Find the masses of the following amounts.
In-s [12.5K]

The mass of 2.15 mol of hydrogen sulphide (H₂S) will be 73.272 gm and the mass of  3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) will be 1.82 gm

<h3>What is Mole ?</h3>

A mole is a very important unit of measurement that chemists use.

A mole of something means you have 6.023 x 10 ²³ of that thing.

  • For 2.15 mol of hydrogen sulphide (H₂S) :

1 mole hydrogen sulphide (H₂S) = 34.08088 grams

Therefore,

2.15 mol of hydrogen sulphide (H₂S) = 34.08088 grams x 2.15 mol

                                                              = 73.272 gm

  • For 3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) ;

1 mol of lead(II) iodide, (PbI₂) = 461.00894 grams

Therefore,

3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) = 461.00894 grams x 3.95 × 10⁻³ mol

                                                                  = 1.82 gm

Hence,The mass of 2.15 mol of hydrogen sulphide (H₂S) will be 73.272 gm and the mass of  3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) will be 1.82 gm

Learn more about mole here ;

brainly.com/question/21323029

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7 0
2 years ago
Preparation the buffer solution: initial pH of buffer solution: ____ Titration of a weak acid with a strong base: initial pH of
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Answer:

pH of buffer solution is 7.0

Initial pH of Weak acid is 3.27

Final pH of weak acid is 3.07

Amount of NaOH added is 1ml

Explanation:

Titration is a process in which acid and base are introduced together until a neutral solution is achieved whose pH value is near to buffer solution which is 7.0, the pH value for acid is below 7 while pH value for base is above 7.

4 0
2 years ago
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