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3 years ago

The _ vapor pressure at high altitudes causes a liquid to boil at a __ temperature.

Chemistry

2 answers:

soldier1979 [14.2K]3 years ago

7 0

Answer:

The reduced vapor pressure at high altitudes causes a liquid to boil at a lower temperature.

Explanation:

A liquid will change its form when its vapor pressure higher than the atmospheric pressure. At higher altitudes, the air pressure will be lower since there will be less air above your head compared to the sea level. This means the atmospheric pressure will be lower, and the vapor pressure needed for the liquid will be reduced.

The pressure is directly proportional to temperature. Since the vapor pressure required is lower, the liquid can start to boil at a lower temperatures.

Nastasia [14]3 years ago

3 0

The _HIGHER__ vapor pressure at high altitudes causes a liquid to boil at a _LOWER___ temperature.

Explanation:

Vapor pressure is the pressure applied by the molecule of a liquid at the surface of the liquid as it transitions into a gaseous phase. When the vapor pressure exceeds the atmospheric pressure, this is when the liquid begins to boil. Therefore when the atmospheric pressure is low, then the liquid will boil at lower temperatures, because the vapor pressure of the liquid will overcome the atmospheric pressure at lower temperatures.

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five atoms of hydrogen are reactants in a chemical reaction. how many atoms of hydrogen will be found in the products of that re

Mkey [24]

Answer:

5 atoms of hydrogen will be found in the products

Explanation:

5 atoms of hydrogen will be found in the products becuase the law of conservation of mass states that mass is neither created nor destroyed in chemical reactions.

6 0

2 years ago

What's the answer ???

lesya692 [45]

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5 0

3 years ago

The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) ⇌ 2NO(g) Kc = 4.3 ×

Anuta_ua [19.1K]

Answer:

$Kc=~1.49x10^3^4}$

Explanation:

We have the reactions:

A: $N_2_(_g_) + O_2_(_g_) 2NO_(_g_)~~~~~~Kc = 4.3x10^-^2^5$

B: $2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~~~Kc = 6.4x10^9$

Our target reaction is:

$4NO_(_g_) N_2_(_g_) + 2NO_2_(_g_)$

We have $NO_(_g_)$ as a reactive in the target reaction and $NO_(_g_)$ is present in A reaction but in the products side. So we have to flip reaction A.

A: $2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}$

Then if we add reactions A and B we can obtain the target reaction, so:

A: $2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}$

B: $2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~Kc=6.4x10^9$

For the final Kc value, we have to keep in mind that when we have to add chemical reactions the total Kc value would be the multiplication of the Kc values in the previous reactions.

$4NO_(_g_) N_2_(_g_) + 2NO_2_(_g_)~~~Kc=\frac{6.4x10^9}{4.3x10^-^2^5}$

$Kc=~1.49x10^+^3^4}$

3 0

2 years ago

A regular 3-d spatial arrangement of points that correspond to atom positions within a crystal is called_______?

Soloha48 [4]

Answer:

Explanation:

Lattice

8 0

1 year ago

Consider the reaction:

goldfiish [28.3K]

Answer:

K = Ka/Kb

Explanation:

P(s) + (3/2) Cl₂(g) <-------> PCl₃(g) K = ?

P(s) + (5/2) Cl₂(g) <--------> PCl₅(g) Ka

PCl₃(g) + Cl₂(g) <---------> PCl₅(g) Kb

K = [PCl₃]/ ([P] [Cl₂]⁽³'²⁾)

Ka = [PCl₅]/ ([P] [Cl₂]⁽⁵'²⁾)

Kb = [PCl₅]/ ([PCl₃] [Cl₂])

Since [PCl₅] = [PCl₅]

From the Ka equation,

[PCl₅] = Ka ([P] [Cl₂]⁽⁵'²⁾)

From the Kb equation

[PCl₅] = Kb ([PCl₃] [Cl₂])

Equating them

Ka ([P] [Cl₂]⁽⁵'²⁾) = Kb ([PCl₃] [Cl₂])

(Ka/Kb) = ([PCl₃] [Cl₂]) / ([P] [Cl₂]⁽⁵'²⁾)

(Ka/Kb) = [PCl₃] / ([P] [Cl₂]⁽³'²⁾)

Comparing this with the equation for the overall equilibrium constant

K = Ka/Kb

5 0

3 years ago

The ___ vapor pressure at high altitudes causes a liquid to boil at a ____ temperature.

The _ vapor pressure at high altitudes causes a liquid to boil at a __ temperature.