Answer:
work done = 117 kJ
Explanation:
given data
mass m = 3 kg
constant pressure P = 200 kPa
temperature T = 200°C
solution
we know that work done by steam is express as
work done = pressure × ΔVolume ....................1
and here ΔVolume = final volume - initial volume
we use here steam table and get at pressure 200 kPa
final specific volume = 1.08052 m³/kg
and
initial specific volume = 0.885735 m³/kg
so here
ΔV = 3 × (1.08052 - 0.885735)
ΔV = 0.584 m³
so put value in equation 1 we get
work done by steam = 200 × 0.584
work done = 117 kJ
The height of the wood is 5 cm. The length is 2 cm and the width its 3 cm. Multiply that and you get 6 cm. The Volume formula is Length times Width times Height. 6 cm times 5 cm makes 30 cm, which is your width.
Answer:
V=I×R
<em>4</em><em>.</em><em>5</em><em> </em><em>=</em><em> </em><em>I×</em><em>9</em>
<em> </em><em> </em><em> </em><em>I</em><em>.</em><em> </em><em>=</em><em> </em><em>4</em><em>.</em><em>5</em><em>/</em><em>9</em>
<em> </em><em> </em><em> </em><em>I</em><em>. </em><em>=</em><em> </em><em>0</em><em>.</em><em>5</em><em> </em><em>A</em>
<em>curre</em><em>nt</em><em> </em><em>is</em><em> </em><em>0</em><em>.</em><em>5</em><em> </em><em>A</em>
Answer:
Converted to an amount of energy equal to 4 million tons times the speed of light squared. ejected into space in a solar wind.
Explanation:
The 4 million tons of mass is converted to the amount of energy that is equal to 4 million tons times the speed of light squared. This energy moves from the sun with the help of solar winds and received by the planets present in the solar system. This solar energy moves in the form of solar radiation because there is no medium for propagation so that's why we can say that the mass is converted into energy that moves in the form of radiation in discrete packets.
Answer:0.669
Explanation:
Given
mass of clock 93 kg
Initial force required to move it 610 N
After clock sets in motion it requires a force of 514 N to keep moving it with a constant velocity
Initially static friction is acting which is more than kinetic friction
thus 613 force is required to overcome static friction
