<em><u>your </u></em><em><u>question</u></em><em><u>:</u></em><em><u> </u></em>
<em>What are the two types of physical fitness?</em>
<em><u>answer:</u></em>
<em>The</em><em> </em><em>two </em><em>types </em><em>of </em><em>phys</em><em>ical </em><em>fitn</em><em>e</em><em>s</em><em>s</em><em> </em><em>are </em><em>Health-related</em><em> physical fitness and Performance-related physical fitness.</em>
Answer:
The crate was being lifted by a height of 1.48 meters.
Explanation:
In an attempt o move a crate;
Force applied = 2470 N
Work done by the force = 3650 J
We know that the work done is defined as the force used to move an object to a distance.
Given the Force used and the work done by that Force, we need to find out the distance the crate was lifted to.
Work done is defined as:
Work = Force*distance covered in the direction of the force
3650 = 2470*distance
distance = 3650/2470
distance = 1.48 meters
elections moves from Stan's hair to the com making it negatively charged.
Answer:
The acceleration of the ball is 666.67 m/s²
Explanation:
It is given that,
Mass of the baseball, m = 0.15 kg
Applied force to it, F = 100 N
We need to find the acceleration of the ball. It can be calculated using Newton's second law of motion as :
F = ma
So, the acceleration of the ball is 666.67 m/s². Hence, this is the required solution.
Answer:
D. half as much
Explanation:
let m and M be the mass of the planets and r be the distance between them.
then: the force of attraction between them is given by,
F = G×m×M/(r^2)
if we keep one mass constant and double the other and also double the distance between them.
the force of attraction becomes:
F1 = 2G×m×M/[(2×r)^2]
= 2G×m×M/[4×(r)^2]
= (1/2)G×m×M/(r^2)
= 1/2×F
therefore, when you double one mass and keep the other mass constant and double the distance between the masses you decrease the force by a factor of 1/2.
