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viktelen [127]
3 years ago
7

Select the correct answer. Which scientist performed the cathode ray experiment leading to the discovery of electrons? A. Dalton

B. Rutherford C. Democritus D. Bohr E. Thomson
Chemistry
2 answers:
MrRa [10]3 years ago
4 0
Hi,
The answer should be letter E, Thomson.
belka [17]3 years ago
4 0

Answer:

Thomson.

Explanation:

J.J.Thomson performed an experiment called cathode ray experiment in which he used a sealed tube fitted with two electrodes.

When a high voltage was applied, the cathodic electrode emitted some particles which moved towards anode. These particles were negatively charged and discovered as electrons.

So he discovered electrons.

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What is the reaction type<br> 2 Mgl2+ Mn(SO3)2 → 2 MgSO3 + Mnl4
Oksana_A [137]

Answer:

The reaction type is double displacement

4 0
2 years ago
7. An element's most stable ion forms an ionic compound with chlorine having the formula XCl2. If the ion of element X has a mas
Serhud [2]

Answer:

The element is strontium and the number of neutrons it have is 51.

Explanation:

Based on the given information, the ionic compound is,  

XCl₂ ⇔ X₂⁺ + 2Cl⁻

X2+ is the ion of the mentioned element

As mentioned in the given question, the number of electrons of the element X is 36 and as seen from the reaction the charge present on the ion is +2. Now the atomic number will be,  

No. of electrons = atomic number - charge

36 = atomic number - 2

Atomic number = 38

Based on the periodic table, the atomic number 38 is for strontium element, and the sign of strontium is Sr. Hence, the element X is Sr.  

Now based on the given information, the mass number of the element is 89. Now the no. of neutrons will be,  

No. of neutrons = mass number - atomic number

= 89 - 38

= 51 neutrons.  

4 0
3 years ago
The correct electron configuration of the O2-ion is
Mnenie [13.5K]
I think it’s A sorry if i’m wrong
6 0
2 years ago
Which statement can be made about the above passage
Korvikt [17]

Answer:

Explanation:

whats the qustion?

5 0
3 years ago
How many moles of oxygen are needed for the complete combustion of 29.2 grams of acetylene?
podryga [215]

Moles of Oxygen= 2.8075 moles

<h3>Further explanation</h3>

Given

29.2 grams of acetylene

Required

moles of Oxygen

Solution

Reaction(Combustion of Acetylene) :

2 C₂H₂ (g) + 5 O₂ (g) ⇒ 4CO₂ (g) + 2H₂O (g)

Mol of Acetylene :

= mass : MW Acetylene

= 29.2 g : 26 g/mol

= 1.123

From equation, mol ratio of Acetylene(C₂H₂) : O₂ = 2 : 5, so mol O₂ :

= 5/2 x mol C₂H₂

= 5/2 x 1.123

= 2.8075 moles

7 0
2 years ago
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