What is the force on a 250 kg elevator that is falling freely at 9.8 m/sec2?
2 answers:
Answer:
Explanation:
The elevator is falling freely and the only force acting on it is weight. So, calculate the weight.
We can do this by multiplying the mass by the acceleration of gravity.
The mass of the elevator is 250 kilograms and the acceleration of gravity is 9.8 meters per second squared.
Substitute the values into the formula.
Multiply.
- 1 kilogram meter per second squared is equal to 1 Newton
- So, our answer of 2450 kg*m/s² is equal to 2450 N
The force of weight on the elevator is <u>2450 Newtons</u>
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Answer:
Explanation:
From the question we are told that:
Crane Length
Crane Mass
Arm extension at lifting end
Arm extension at counter weight end
Load
Generally the equation for Torque Balance is mathematically given by
Answer:
1.
2.
3.The results from part 1 and 2 agree when r = R.
Explanation:
The volume charge density is given as
We will investigate this question in two parts. First r < R, then r > R. We will show that at r = R, the solutions to both parts are equal to each other.
1. Since the cylinder is very long, Gauss’ Law can be applied.
The enclosed charge can be found by integrating the volume charge density over the inner cylinder enclosed by the imaginary Gaussian surface with radius ‘r’. The integration of E-field in the left-hand side of the Gauss’ Law is not needed, since E is constant at the chosen imaginary Gaussian surface, and the area integral is
where ‘h’ is the length of the imaginary Gaussian surface.
2. For r> R, the total charge of the enclosed cylinder is equal to the total charge of the cylinder. So,
3. At the boundary where r = R:
As can be seen from above, two E-field values are equal as predicted.