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ELEN [110]
3 years ago
8

What is the force on a 250 kg elevator that is falling freely at 9.8 m/sec2?​

Physics
2 answers:
Anettt [7]3 years ago
7 0

Answer:

\boxed {\boxed {\sf 2450 \ Newtons }}

Explanation:

The elevator is falling freely and the only force acting on it is weight. So,  calculate the weight.

We can do this by multiplying the mass by the acceleration of gravity.

W=m*g

The mass of the elevator is 250 kilograms and the acceleration of gravity is 9.8 meters per second squared.

m= 250 \ kg \\g= 9.8 \ m/s^2

Substitute the values into the formula.

W= 250 \ kg * 9.8 \ m/s^2

Multiply.

W=2450 \ kg*m/s^2

  • 1 kilogram meter per second squared is equal to 1 Newton
  • So, our answer of 2450 kg*m/s² is equal to 2450 N

W= 2450 \ N

The force of weight on the elevator is <u>2450 Newtons</u>

Viefleur [7K]3 years ago
6 0

Answer:

Since it is falling freely, the only force on it is its weight, w.

w = m × g = 250 kg × 9.8 m/s^2 = 2450 Newton/N

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1. Mike wears an 8.50 kg backpack while scaling a cliff. After 90 minutes, Mike is 11.2 m above the starting point.
svet-max [94.6K]

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a. 952Joules

b. 8008 joules

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2 years ago
The sound intensity of a certain type of food processor in normally distributed with standard deviation of 2.9 decibels. If the
Maru [420]

Answer: (48.41,\ 52.19)

Explanation:

The confidence interval for population mean is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

Given : Sample size : n=9

Sample mean : \ovreline{x}=50.3\text{ decibels}

Standard deviation : \sigma=2.9\text{ decibels }

Significance level : \alpha=1-0.95=0.05

Critical value : z_{\alpha/2}=z_{0.025}=1.96

Now, the 95% confidence interval estimate of the (true, unknown) mean sound intensity of all food processors of this type :-

50.3\pm (1.96)\dfrac{2.9}{\sqrt{9}}\\\\\approx50.3\pm1.89\\\\=(50.3-1.89,\ 50.3+1.89)=(48.41,\ 52.19)

6 0
3 years ago
A fireworks shell is accelerated from rest to a velocity of 68.0 m/s over a distance of 0.230 m.
Ugo [173]

Answer:

(A) 10052.2 m/s²

(B)  0.00678 seconds

Explanation:

From the question,

(A) Applying

V² = U²+2as..................... Equation 1

Where V = Final velocity, U = Initial velocity, a = acceleration due to gravity, s = distance.

make a the subject of the  equation

a = (V²-U²)/2s........................ Equation 2

Given: U = 0 m/s( from rest), V = 68 m/s, s = 0.230 m

Substitute these values into equation 2

a = (68²-0²)/(2×0.230)

a = 10052.2 m/s²

(B) Using,

a = (V-U)/t......................... Equation 3

Where t= time.

make t the subject of the equation

t = (V-U)/a......................... Equation 4

Given: V = 68 m/s, U = 0 m/s, a = 10052.2

Substitute into equation 4

t = (68-0)/10052.2

t = 0.00678 seconds

5 0
3 years ago
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