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2 years ago

What is the force on a 250 kg elevator that is falling freely at 9.8 m/sec2?

Physics

2 answers:

Anettt [7]2 years ago

7 0

Answer:

$\boxed {\boxed {\sf 2450 \ Newtons }}$

Explanation:

The elevator is falling freely and the only force acting on it is weight. So, calculate the weight.

We can do this by multiplying the mass by the acceleration of gravity.

$W=m*g$

The mass of the elevator is 250 kilograms and the acceleration of gravity is 9.8 meters per second squared.

$m= 250 \ kg \\g= 9.8 \ m/s^2$

Substitute the values into the formula.

$W= 250 \ kg * 9.8 \ m/s^2$

Multiply.

$W=2450 \ kg*m/s^2$

1 kilogram meter per second squared is equal to 1 Newton
So, our answer of 2450 kg*m/s² is equal to 2450 N

$W= 2450 \ N$

The force of weight on the elevator is <u>2450 Newtons</u>

Viefleur [7K]2 years ago

6 0

Answer:

Since it is falling freely, the only force on it is its weight, w.

w = m × g = 250 kg × 9.8 m/s^2 = 2450 Newton/N

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Nikolay [14]

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